A. 2
B. -2
C. 1
D. No solution
Tan (tan-1 1/2+ tan-11/3) =
The range of f(x)= Sin-1x-cos-1x + Tan-1x is
If Tan-1(x-1/x-2)+ Cot-1 (x+2/x+1)=π/4, then x=
The domain of f(x)=Tan-1 √x(x+3) + sin-1√x2+3x+1 is
Sin-1(-√2/2) + Cos-1(-1/2)-Tan-1(-√3)-Cot-1(1/√3) =
Sec-1√34/5+ Cosec-1√17 =
Tan [cos-1 4/5+tan-1 2/3] =
If Sec-1(x/a)- Sec-1(x/b)= Sec-1 b- Sec-1a then x=
Sin-1(sin 2π/3) =
sin-1(2cos2 x-1)cos-1(1-2sin2 x)