A. 1/√2
B. ±1/√2
C. ±1/√3
D. 1/√3
The domain of f(x)=Tan-1 √x(x+3) + sin-1√x2+3x+1 is
Sin-1(-√2/2) + Cos-1(-1/2)-Tan-1(-√3)-Cot-1(1/√3) =
Sec-1√34/5+ Cosec-1√17 =
Tan [cos-1 4/5+tan-1 2/3] =
If Sec-1(x/a)- Sec-1(x/b)= Sec-1 b- Sec-1a then x=
Sin-1(sin 2π/3) =
sin-1(2cos2 x-1)cos-1(1-2sin2 x)
4 Tan-1 1/5- Tan-1 1/70+Tan-1 1/99 =
Tan (π/4+1/2cos-1a/b) +tan (π/4-1/2cos-1a/b) =
If 2Tan-1(cos x) = Tan-1(2 cosec x) then x=