If Tan^-1(x-1/x-2)+ Cot^-1 (x+2/x+1)=π/4, then x=

The domain of f(x)=Tan^-1 √x(x+3) + sin^-1√x²+3x+1 is

Sin^-1(-√2/2) + Cos^-1(-1/2)-Tan^-1(-√3)-Cot^-1(1/√3) =

Sec^-1√34/5+ Cosec^-1√17 =

Tan [cos^-1 4/5+tan^-1 2/3] =

If Sec^-1(x/a)- Sec^-1(x/b)= Sec^-1 b- Sec^-1a then x=

Sin^-1(sin 2π/3) =

sin^-1(2cos² x-1)cos^-1(1-2sin² x)

4 Tan^-1 1/5- Tan^-1 1/70+Tan^-1 1/99 =

Tan (π/4+1/2cos^-1a/b) +tan (π/4-1/2cos^-1a/b) =