A. 120 m
B. 240 m
C. 480 m
D. 960 m
Speed = [ 54 x (5/18) ] m/sec = 15 m/sec
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be z metres
Then, (z + 300) / 36 = 15
=> z + 300 = 540
=> z = 240 m
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