A. 230 m
B. 240 m
C. 250 m
D. 260 m
Relative speed = (120 + 80) km/hr
= [ 200 x (5/18) ] m/sec
= (500/9) m/sec
Let the length of the other train be z metres
Then, (z + 270) / 9 = 500 / 9
=> z + 270 = 500
=> z = 230
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