A. 30 km/hr
B. 45 km/hr
C. 60 km/hr
D. 75 km/hr
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec
=> (100 + 100) / 8 = 3x
=> 24x = 200
=> x = 25/3
So, speed of the faster train = (50/3) m/sec
= (50/3) x (18/5) km/hr
= 60 km/hr