1.  π

2.  π/2

3.  π/4

4.  3π/2

4

&#960;/4

Explanation :
No Explanation available for this question

1.  0

2.  1

3.  (e2-1)/2e

4.  (e2+2)/2e

4

(e2-1)/2e

Explanation :
No Explanation available for this question

The solution of (x2 + y2)dx = 2xy dy is :

1.  c(x2 - y2) = x

2.  c(x2 + y2) = x

3.  c(x2 - y2) = y

4.  c(x2 + y2) = y

4

c(x<sup>2</sup> - y<sup>2</sup>) = x

Explanation :
No Explanation available for this question

The solution of (1 + x2)dy/dx + 2xy - 4x2 = 0 is :

1.  3x(1 + y2) = 4y3 + c

2.  3y(1 + x2) = 4x3 + c

3.  3x(1 - y2) = 4y3 + c

4.  3y(1 + y2) = 4x3 + c

4

3y(1 + x<sup>2</sup>) = 4x<sup>3</sup> + c

Explanation :
No Explanation available for this question

The solution of dx/dy + x/y =x2 is :

1.  1/y = cx - x log x

2.  1/x = cy - y log y

3.  1/x = cx + x log y

4.  1/y = cx - y log x

4

1/x = cy - y log y

Explanation :
No Explanation available for this question

If f : R→ C is defined by f(x) = e2ix  for x є R, then f is (where C denotes the set of all complex numbers)

1.  one-one

2.  onto

3.  one-one and onto

4.  neither one-one nor onto

4

neither one-one nor onto

Explanation :
No Explanation available for this question

If f : R → R and g : R→ R are defined by f(x) = | x | And g (x) = [x - 3] for x є R, then{ g(f(x)) : -8/5 < x < 8/5 } =

1.  {0, 1}

2.  { 1, 2}

3.  {-3, -2}

4.  {2, 3}

4

{-3, -2}

Explanation :
No Explanation available for this question

If f :[- 6, 6] → R is defined by f(x) = x2 - 3 for  x є R, then ( fofof)(-1) + ( fofof)(0) + ( fofof)(1) is equal to

1.  f(4√2)

2.  f(3√2)

3.  f(2√2)

4.  f(√2)

4

f(4&#8730;2)

Explanation :
No Explanation available for this question

Given that a, b є {0,1,2,....9} with a+b ≠ 0 and that  (a + b/10)x = (a/10 + b/100)y = 1000. Then, 1/x - 1/y is equal to

1.  1

2.  1/2

3.  1/3

4.  1/4

4

1/3

Explanation :
No Explanation available for this question

1.  1

2.  2

3.  3

4.  4

4