Reasoning - Number Letter Series Test

Test Instructions :

1. The Test is 1hr duration.
2. The Test Paper consists of 30 questions. The maximum marks are 30.
3. All the questions are multiple choice question type with three options for each question.
4. Out of the three options given for each question, only one option is the correct answer.
5. Each question is allotted 1 mark for each correct response.
6. 0.25 will be deducted for incorrect response of each question.
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   Time Left : 00 : 30    : 00

Boxes numbered 1, 2, 3, 4 and 5 are kept in a row, and they which are to be filled with either a red or ablue ball, such that no two adjacent boxes can be filled with blue balls. Then how many different arrangements are possible, given that all balls of a given colour are exactly identical in all respects?

  

  

  

  

258  130  66  ?  18  10

  

  

  

  

1, 1, 2, 6, 24,?, 720

  

  

  

  

D  F  I  M  R  ?

  

  

  

  

Three numbers are in G.P. Their sum is 28 and product is 512. The numbers are

  

  

  

  

1 3 9 31 128 651 3913

  

  

  

  

  

I  M  Q ?

  

  

  

  

A,G,L,P,S …?

  

  

  

  

Certain number of girls made a plan for one day trip. Their budget to spend on snacks was Rs. 192. But, one of them did not turn up for the trip. Because of this, the remaining girls had to contribute Rs. 8 each in extra. Find out the number of girls who went for the trip.

  

  

  

  

  

1W  2V  3U  5T  ?  13R

  

  

  

  

2 3 5 8 14 23 41 69.

  

  

  

  

  

0 1 9 36 99 225 441

  

  

  

  

  

2  4  8  14  22  ?

  

  

  

  

36 216 64.8 388.8 A 699.84 209.952 A÷36 ?

  

  

  

  

  

4, 9, 20, 43, 90,               .

  

  

  

  

Complete the following series.1, 1, 4, 12, 27, 51,     .

  

  

  

  

P3C, R5F, T8I, V12L, ?

  

  

  

  

HV  GT FR EP DN    ?

  

  

  

  

80, 75, 65, 50,               .

  

  

  

  

625, 5, 125, 25, 25, ?, 5

  

  

  

  

2  3  4  6  8  ?  16  24

  

  

  

  

1, 1,  3/4  ,1/2,5/16,.........................,

  

  

  

  

3 2 3 6 12 37.5 115.5

  

  

  

  

  

Typist : Typewriter : : Writer: ?

  

  

  

  

625, 5, 125, 25, 25, ?, 5

  

  

  

  

The sum of the series: 1² + 2² + 3² + 4² + ……+ 15² is

  

  

  

  

0, 11, 26, 45,               .

  

  

  

  

42 3.5 73 26.25 118.125

  

  

  

  

  

If the nth term of an A.P. is 4n + 1, then the common difference is

  

  

  

  

f(6, 4) equals to

  

  

  

  

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