Eamcet - Maths - Trigonometric Ratios And Identities Test

Test Instructions :

1. The Test is 1hr duration.
2. The Test Paper consists of 30 questions. The maximum marks are 30.
3. All the questions are multiple choice question type with three options for each question.
4. Out of the three options given for each question, only one option is the correct answer.
5. Each question is allotted 1 mark for each correct response.
6. 0.25 will be deducted for incorrect response of each question.
Start Test

   Time Left : 00 : 30    : 00

If  (1-tan 20 cot220)/(tan 1520- cot 880)= k√3, then value of k is

  

  

  

  

The value of cos θ+3√2 sin( θ+π/4)+6 lies between

  

  

  

  

cos2A+cos2 (1200+A)+ cos2 (1200-A)=

  

  

  

  

If (sin x+ cos x)/(cos3 x)= a tan3 x+ b tan2 x+c tan x+d then a+b+c+d=

  

  

  

  

If sin x+sin y=1/4, sin x- siny=1/5, then 4 cot(x-y/2)=

  

  

  

  

If sin θ+ cos θ=a then sin4 θ+ cos 4 θ=

  

  

  

  

4(cos3 200 +cos34 00) =

  

  

  

  

cos 10+ cos 20+ cos 30+...+ cos 1790=

  

  

  

  

If tan2 A= 2 tan2 B+1, then cos 2A+ sin2 B=

  

  

  

  

If A+B+C= 1800 then sin2 A/2+ sin 2 B/2 - sin2 C/2=

  

  

  

  

If A+B+C=1800 then sin A+sin B+sin C=

  

  

  

  

If A+B+C= 1800 then sin 2A+ sin 2B- sin 2C=

  

  

  

  

If A+B+C+D= 2π, then -4 cos (A+B/2) sin (A+C/2) cos (A-D/2)=

  

  

  

  

The maximum value of 5 cos x+ 3 cos (x- 600)+7 is

  

  

  

  

8 sin θ cos θ cos 2θ cos 4θ=

  

  

  

  

2 cos 540. Sin 660=

  

  

  

  

If 4 sin(600+ θ) sin(600-θ)-1= kcos 2θ, the value of k is

  

  

  

  

If tan A=18/17, tan B= 1/35 then tan(A-B)=

  

  

  

  

(sin(n+1)α- sin(n-1)α)/ (cos(n+1)α+ 2 cos nα+ cos(n-1)α)=

  

  

  

  

cos2 360+ cos2 720=

  

  

  

  

cos (θ + α).cos (θ - α)+ sin (θ + α). sin(θ - α)=

  

  

  

  

√3 cosec 200- sec 200 =

  

  

  

  

(sin 4θ)/(sin θ)=

  

  

  

  

1- cos A+ cos B- cos (A+B)/1+cos A- cos B- cos(A+B)=

  

  

  

  

2 sec2 θ- sec4 θ- 2 cosec2 θ+ cosec4θ=

  

  

  

  

If A=cos 150- cos 750,B= tan 150+ tan 750, C= cos2450 – sin2 150 then ascending order is

  

  

  

  

In ΔABC, 1+4 sin(π-A/4)sin(π-B/4)sin(π-C/4)=

  

  

  

  

sin5θ/sinθ is equal to

  

  

  

  

If A+B+C =900 then (cot A+cot B+cot C)/(cot A cot B cot C) =

  

  

  

  

A student has to answer 10 out of 13 questions in an examination choosing at least 5 questions from the first 6 questions. The number of choice available to the student is

  

  

  

  

Note:
  • Click the 'Submit Test' button given in the bottom of this page to Submit your answers.
  • Test will be submitted automatically if the time expired.
  • Don't refresh the page.