### Eamcet - Maths - Inverse Trigonometric Functions Test

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Two angles ofa triangle are Cot-1 2 and Cot-1 3.Then the third angle is

tan (1/2 cos-1(0)) =

If Sec-1(x/a)- Sec-1(x/b)= Sec-1 b- Sec-1a then x=

Tan (tan-1 1/2+ tan-11/3) =

Sin-1(-√2/2) + Cos-1(-1/2)-Tan-1(-√3)-Cot-1(1/√3) =

Sin (2Tan-13/4) =

If 2Tan-1(cos x) = Tan-1(2 cosec x) then x=

If sin-1 (3/5)+sin-1(5/13)= sin-1 x, then x=

The range of f(x)= Sin-1x-cos-1x + Tan-1x is

Tan-1 1/3+ Tan-1 1/5+ Tan-1 1/7+ Tan-1 1/8 =

The equation Sin-1 x- Cos-1 x=Cos-1 (√3/2) has

The value of Cot [Cot-1 7+ Cot-1 8+ Cot-1 (18)] is

The domain of Cos-1 (2/2+sinx) in [0,2π] is

Tan-1 5/6+ 1/2 Tan-1 11/60 =

sin-1(2cos2 x-1)cos-1(1-2sin2 x)

The domain of f(x)=Tan-1 √x(x+3) + sin-1√x2+3x+1 is

The ascending order of A= Sin-1(sin 8π/7),B= Cos-1(cos 8π/7), ), C=Tan-1(tan 8π/7) is

The domain of Sinh-1 2x is

Let Then which one of the following is true

If cos-1(3/5) - sin-1(4/5) = cos-1(x), then x

Sin (4 arc Tan-11/3) =

The range of Sin-1 x - Cos-1 x is

If θ= Sin-1 x+ Cos-1 x+ Tan-1 x, 0≤x≤1, then the smallest interval in which θ lies is given by

If Sin-1 x+ Sin-1 y+ Sin-1 z=π then x2+y2+z2+2xyz=

If Tan-1 x+ Tan-1 y+ Tan-1 z=π, then x+y+z=

Tan [cos-1 4/5+tan-1 2/3] =

Sin-1(3/5)+Sin-1(8/17)=

If Cot-1 4/3+Cot-1 5/3= Tan-1 k, then k=

Cos-1(63/65) + 2 Tan-1(1/5) =

4 Tan-1 1/5- Tan-1 1/239 =

Note: