### Eamcet - Maths - Inverse Trigonometric Functions Test

#### Time Left : 00 : 30    : 00

The range of Sin-1 5x is

If Sec-1(x/a)- Sec-1(x/b)= Sec-1 b- Sec-1a then x=

If cos-1 x= cot-1(4/3)+Tan-1(1/7), then x=

Sin-1(-√2/2) + Cos-1(-1/2)-Tan-1(-√3)-Cot-1(1/√3) =

Sin-1 (16/65) +2 Tan-1 (1/5) =

Tan [cos-1 4/5+tan-1 2/3] =

4 Tan-1 1/5- Tan-1 1/239 =

The equation Sin-1 x- Cos-1 x=Cos-1 (√3/2) has

The domain of f(x)=Tan-1 √x(x+3) + sin-1√x2+3x+1 is

Cos-1(63/65) + 2 Tan-1(1/5) =

The value of Cot [Cot-1 7+ Cot-1 8+ Cot-1 (18)] is

If tan-1 2, tan-13 are two angles of a triangle, then the third angle is

If Tan-1(x-1/x-2)+ Cot-1 (x+2/x+1)=π/4, then x=

The domain of Cosh-1 3x is

IfTan-1(1/7)= α, Tan-1(1/3)=β then cos 2α =

Tan (tan-1 1/2+ tan-11/3) =

If 2Tan-1(cos x) = Tan-1(2 cosec x) then x=

Sin-1(3/5)+Sin-1(8/17)=

The domain of Cos-1 (2/2+sinx) in [0,2π] is

If Tan-1 x+ Tan-1 y+ Tan-1 z=π, then x+y+z=

If Cot-1 4/3+Cot-1 5/3= Tan-1 k, then k=

If Tan-1(x+1/x-1)+Tan-1(x-1/x)+ Tan-1(1/3), then x=

Tan-1 2+ Tan-1 3 =

The range of Sin-1 x+ Cos-1 x is

If Tan-1 (sec x + tan x)=π/4+kx then k=

Tan-1 1/3+ Tan-1 1/5+ Tan-1 1/7+ Tan-1 1/8 =

The range of Sin-1 x - Cos-1 x is

The domain of Sinh-1 2x is

tan (1/2 cos-1(0)) =

4 Tan-1 1/5- Tan-1 1/70+Tan-1 1/99 =

Note: