Eamcet - Maths - Inverse Trigonometric Functions Test

Test Instructions :

1. The Test is 1hr duration.
2. The Test Paper consists of 30 questions. The maximum marks are 30.
3. All the questions are multiple choice question type with three options for each question.
4. Out of the three options given for each question, only one option is the correct answer.
5. Each question is allotted 1 mark for each correct response.
6. 0.25 will be deducted for incorrect response of each question.
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The range of Sin-1 5x is

  

  

  

  

If Sec-1(x/a)- Sec-1(x/b)= Sec-1 b- Sec-1a then x=

  

  

  

  

If cos-1 x= cot-1(4/3)+Tan-1(1/7), then x=

  

  

  

  

Sin-1(-√2/2) + Cos-1(-1/2)-Tan-1(-√3)-Cot-1(1/√3) =

  

  

  

  

Sin-1 (16/65) +2 Tan-1 (1/5) =

  

  

  

  

Tan [cos-1 4/5+tan-1 2/3] =

  

  

  

  

4 Tan-1 1/5- Tan-1 1/239 =

  

  

  

  

The equation Sin-1 x- Cos-1 x=Cos-1 (√3/2) has

  

  

  

  

The domain of f(x)=Tan-1 √x(x+3) + sin-1√x2+3x+1 is

  

  

  

  

Cos-1(63/65) + 2 Tan-1(1/5) =

  

  

  

  

The value of Cot [Cot-1 7+ Cot-1 8+ Cot-1 (18)] is

  

  

  

  

If tan-1 2, tan-13 are two angles of a triangle, then the third angle is

  

  

  

  

If Tan-1(x-1/x-2)+ Cot-1 (x+2/x+1)=π/4, then x=

  

  

  

  

The domain of Cosh-1 3x is

  

  

  

  

IfTan-1(1/7)= α, Tan-1(1/3)=β then cos 2α =

  

  

  

  

Tan (tan-1 1/2+ tan-11/3) =

  

  

  

  

If 2Tan-1(cos x) = Tan-1(2 cosec x) then x=

  

  

  

  

Sin-1(3/5)+Sin-1(8/17)=

  

  

  

  

The domain of Cos-1 (2/2+sinx) in [0,2π] is

  

  

  

  

If Tan-1 x+ Tan-1 y+ Tan-1 z=π, then x+y+z=

  

  

  

  

If Cot-1 4/3+Cot-1 5/3= Tan-1 k, then k=

  

  

  

  

If Tan-1(x+1/x-1)+Tan-1(x-1/x)+ Tan-1(1/3), then x=

  

  

  

  

Tan-1 2+ Tan-1 3 =

  

  

  

  

The range of Sin-1 x+ Cos-1 x is

  

  

  

  

If Tan-1 (sec x + tan x)=π/4+kx then k=

  

  

  

  

Tan-1 1/3+ Tan-1 1/5+ Tan-1 1/7+ Tan-1 1/8 =

  

  

  

  

The range of Sin-1 x - Cos-1 x is

  

  

  

  

The domain of Sinh-1 2x is

  

  

  

  

tan (1/2 cos-1(0)) =

  

  

  

  

4 Tan-1 1/5- Tan-1 1/70+Tan-1 1/99 =

  

  

  

  

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