Eamcet - Maths - Inverse Trigonometric Functions Test

Test Instructions :

1. The Test is 1hr duration.
2. The Test Paper consists of 30 questions. The maximum marks are 30.
3. All the questions are multiple choice question type with three options for each question.
4. Out of the three options given for each question, only one option is the correct answer.
5. Each question is allotted 1 mark for each correct response.
6. 0.25 will be deducted for incorrect response of each question.
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Two angles ofa triangle are Cot-1 2 and Cot-1 3.Then the third angle is

  

  

  

  

tan (1/2 cos-1(0)) =

  

  

  

  

If Sec-1(x/a)- Sec-1(x/b)= Sec-1 b- Sec-1a then x=

  

  

  

  

Tan (tan-1 1/2+ tan-11/3) =

  

  

  

  

Sin-1(-√2/2) + Cos-1(-1/2)-Tan-1(-√3)-Cot-1(1/√3) =

  

  

  

  

Sin (2Tan-13/4) =

  

  

  

  

If 2Tan-1(cos x) = Tan-1(2 cosec x) then x=

  

  

  

  

If sin-1 (3/5)+sin-1(5/13)= sin-1 x, then x=

  

  

  

  

The range of f(x)= Sin-1x-cos-1x + Tan-1x is

  

  

  

  

Tan-1 1/3+ Tan-1 1/5+ Tan-1 1/7+ Tan-1 1/8 =

  

  

  

  

The equation Sin-1 x- Cos-1 x=Cos-1 (√3/2) has

  

  

  

  

The value of Cot [Cot-1 7+ Cot-1 8+ Cot-1 (18)] is

  

  

  

  

The domain of Cos-1 (2/2+sinx) in [0,2π] is

  

  

  

  

Tan-1 5/6+ 1/2 Tan-1 11/60 =

  

  

  

  

sin-1(2cos2 x-1)cos-1(1-2sin2 x)

  

  

  

  

The domain of f(x)=Tan-1 √x(x+3) + sin-1√x2+3x+1 is

  

  

  

  

The ascending order of A= Sin-1(sin 8π/7),B= Cos-1(cos 8π/7), ), C=Tan-1(tan 8π/7) is

  

  

  

  

The domain of Sinh-1 2x is

  

  

  

  

Let Then which one of the following is true

  

  

  

  

If cos-1(3/5) - sin-1(4/5) = cos-1(x), then x

  

  

  

  

Sin (4 arc Tan-11/3) =

  

  

  

  

The range of Sin-1 x - Cos-1 x is

  

  

  

  

If θ= Sin-1 x+ Cos-1 x+ Tan-1 x, 0≤x≤1, then the smallest interval in which θ lies is given by

  

  

  

  

If Sin-1 x+ Sin-1 y+ Sin-1 z=π then x2+y2+z2+2xyz=

  

  

  

  

If Tan-1 x+ Tan-1 y+ Tan-1 z=π, then x+y+z=

  

  

  

  

Tan [cos-1 4/5+tan-1 2/3] =

  

  

  

  

Sin-1(3/5)+Sin-1(8/17)=

  

  

  

  

If Cot-1 4/3+Cot-1 5/3= Tan-1 k, then k=

  

  

  

  

Cos-1(63/65) + 2 Tan-1(1/5) =

  

  

  

  

4 Tan-1 1/5- Tan-1 1/239 =

  

  

  

  

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