Eamcet - Maths - Binomial Theorem Test

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C1/1 – C2/2 + C3/3 – C4/4 +………. +(-1)n-1 Cn/n =

k.C0+k2.C1/2+K2. C2/3+.…………+kn+1.Cn/n+1 =

1.nC0+41.nC1+42.nC2+43.nC3+……..+4n.nCn =

The 4th term of (1-2x)-1 when x=1/3 is

If the first three terms of (1+ax)n are 1,6x,6x2 then (a,n)=

(2-)5 + (2+)5 =

The coefficient of x6 in (1+x+x2+x3+x4+x5)6 is

If the 3rd, 4th and 5th terms of (x+a)n are 60, 160 and 240 respectively then (x,a,n)=

The positive integer which is just greater than (1+0.0001)10000 is

The coefficient of x5 in the expression of (1+x)21+(1+x)22+……+(1+x)30 is

If the sum of odd terms and the sum of even terms in the expansion of (x+a)n are p and q respectively then p2+q2=

The number of non zero terms in the expansion of (x+a)100 + (x-a)100 is

If Tr+1 is the term independent of x in (3x-5/x3)8 then r=

Larger of 199100+200100and 201100 is

C2+C4+C6+……….. =

The 3rd term of 4 (3x-y3)is

The coefficients of three consecutive terms in the expansion of (1+x)n are in the ratio 1:7:42, then n=

The point which divides the line segment joining the points( 1,-1,2), (2,3,7) in the ratio -2:3 is

C0+C1/2+C3/3+ …………Cn/n+1+ =

Sum of the last 20 coefficients in the expansion of (1+x)39, when expanded in ascending powers of x, is

Middle term in the expansion of (2x-3/x)15is

The term independent of x in the expansion of (1+x+2x3)(3x2/2-1/3x/)9 is

The sum of the coefficients of even powers of x in the expansion of (1+x+x2)15 is

(1.03)19 =

C0+4.C1+7.C2+……(n+1) terms =

2.C0+22.C1/2+23.C3/3+……..+2n+1.Cn/n+1 =

The 4th term of 6(x+2/x2)6 is

If the coefficients of 2nd, 3rd, 4th terms in the expansion of (1+x)2n are in A.P. then

C0+C1/2+C2/22+C3/23+.....Cn/2n

(2n+1)C0-(2n+1)C1+…………. -(2n+1)C2n =

Note: