# The first algorithm for Linear Programming was given by:

1.  Bellman

2.  Dantzing

3.  Kulm

4.  von Neumann

4

Dantzing

Explanation :
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# We wish to solve x2 - 2 = 0 by Newton Raphson technique. Let the initial guess bx0 = 1.0 subsequent estimate of x (i.e. x1) will be:

1.  1.414

2.  1.5

3.  2.O

4.  None of the above

4

1.5

Explanation :
No Explanation available for this question

1.  6

2.  5

3.  -3

4.  -4

4

-4

Explanation :
No Explanation available for this question

# The acceleration of the particle in this field, occupying point (1,1) a t time t = 1 will be

1.

2.

3.

4.

4 Explanation :
No Explanation available for this question

1.  2/3

2.  π/8

3.  π/2

4.  π/4

4

2/3

Explanation :
No Explanation available for this question

# The above equation is a

1.  partial differential equation

2.  Non-linear differential equation

3.  non-homogeneous differential equation

4.  Ordinary differential equation

4

Ordinary differential equation

Explanation :
No Explanation available for this question

# Four arbitrary points (x1, y1),(x2, y2),(x3, y3),(x4,y4)are given in the x, y -plane. Using the method of least squares, if, regressing y upon x gives the fitted line y = a x + b; and regressing y upon x gives the fitted line y = a x + b; and regressing x upon y gives the fitted line x = cy+ d, then

1.  the two fitted lines must coincide

2.  the two fitted lines need not coincide

3.  it is possible that ac = O

4.  a must be 1/c

4

a must be 1/c

Explanation :
No Explanation available for this question

# A thin walled cylindrical vessel of wall thickness t and diameter d is filled with gas to a gauge pressure of p. the maximum shear stress on the vessel wall will then be

1.  pd/t

2.  pd/2t

3.  pd/4t

4.  pd/8t

4

pd/8t

Explanation :
No Explanation available for this question

# A lean elastic beam of given flexural rigidity, EI, is loaded by a single force F a s shown in Fig.2.8. How many boundary conditions are necessary to determine the deflected centerline of the bea m

1.  5

2.  4

3.  3

4.  2

4

4

Explanation :
No Explanation available for this question