A simply supported beam of span L and flexural rigidity EI, carries a unit point of load at its centre. The strain energy in the beam due to bending is

1.  L3/48 EI

2.  L3/192 EI

3.  L3/96 EI

4.  L3/16 EI

View Answer  
4
Correct Answer :

L3/96 EI


Explanation :
No Explanation available for this question

In a two dimensional stress system, it is assumed that the principal stresses σ1 and σ2 are such that σ1 >σ2; then according to the maximum shear stress theory, the failure occurs when (Where σy is yield stress, υ is Poisson’s ratio and E modulus of elasticity)

1.  1/E [σ1-υσ2] ≥ σy/E

2.  [σ12+σ22+ 2υ σ1σ2] ≥ σ2y

3.  [σ1-σ2] ≥ σy

4.  [σ12+σ22-σ1σ2] ≥ σy

View Answer  
4
Correct Answer :

[σ1-σ2] ≥ σy


Explanation :
No Explanation available for this question

The total strain energy per unit volume may be written as

1.  1/E[σ12+σ22+σ32 -2υ(σ1σ2+ σ2σ3+ σ3σ1)]

2.  1/2E[σ12+σ22+σ32 -υ(σ1σ2+ σ2σ3+ σ3σ1)]

3.  2/E[σ12+σ22+σ32 -υ(σ1σ2+ σ2σ3+ σ3σ1)]

4.  1/2E[σ12+σ22+σ32 -2υ(σ1σ2+ σ2σ3+ σ3σ1)]

View Answer  
4
Correct Answer :

1/2E[σ12+σ22+σ32 -2υ(σ1σ2+ σ2σ3+ σ3σ1)]


Explanation :
No Explanation available for this question

In strained body, three principal stresses at appoint are denoted by σ1, σ2 and σ3 such that σ1>σ2 >σ3. If σ0 denoted yield stress, then according to the maximum sheer stress theory

1.  σ1 -σ2 =σ0

2.  σ1 -σ3 =σ0

3.  σ2 -σ3 =σ0

4.  (σ1+σ3)/2 =σ0

View Answer  
4
Correct Answer :

σ1 -σ3 =σ0


Explanation :
No Explanation available for this question

If the strain energy absorbed in a cantilever beam in bending under its own weight is K times greater than the strain energy absorbed in an identical simply supported beam in bending under its own weight, them the magnitude of K is

1.  2

2.  4

3.  6

4.  8

View Answer  
4
Correct Answer :

6


Explanation :
No Explanation available for this question

The rectangular column shown in the above figure carries a load ‘P’ having eccentricities ex and ey along the x-axis and y-axis respectively. The stress at any point (x, y) is given by

1.  p/bd [1+(12ey.y)/d2 + (12ex.x)/b2]

2.  p/bd [1+(12ey.y)/b2 + (12ex.x)/d2]

3.  p/bd [1+(6ey.y)/d2 + (6ex.x)/b2]

4.  p/bd [1+6ey.y)/b2 + (6ex.x)/d2]

View Answer  
4
Correct Answer :

p/bd [1+(12ey.y)/d2 + (12ex.x)/b2]


Explanation :
No Explanation available for this question

In the case of an axially loaded column machined for full bearing, the fastenings connecting the column to the base plates in gusseted base are designed for

1.  100% of the column load

2.  50% of the column load

3.  25% of the column load

4.  Erection conditions only

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4
Correct Answer :

50\% of the column load


Explanation :
No Explanation available for this question

Given that PE = crippling load given Euler Pc = load at failure due to direct compression PR = load in accordance with the Rankine’s criterion of failure Then PR is given by

1.  (PE +PC)/2

2.  √( PE ×PC)

3.  (PE .PC)/ PE +PC

4.  None of these

View Answer  
4
Correct Answer :

(PE .PC)/ PE +PC


Explanation :
No Explanation available for this question

A hollow circular section of a column has external and internal diameters D and d respectively. It is subjected to a compressive load having an eccentricity e. For no tension condition at the base, which one of the following conditions should be satisfied

1.  e < ( (D2+d2)/4√D.d)

2.  e < ((D2+d2)/4√D.d)

3.  e < ((D/3+d/4)/2)

4.  e < ((D2+d2)/8D)

View Answer  
4
Correct Answer :

e < ((D2+d2)/4√D.d)


Explanation :
No Explanation available for this question

A propeller shaft is subjected to maximum compressive direct stress of 20N/mm2 and maximum shear stress of 80 N/mm2 due to torque. The maximum tensile stress induced is closer to

1.  70 N/mm2

2.  60 N/mm2

3.  50 N/mm2

4.  140 N/mm2

View Answer  
4
Correct Answer :

140 N/mm2


Explanation :
No Explanation available for this question
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