# A simply supported beam of span L and flexural rigidity EI, carries a unit point of load at its centre. The strain energy in the beam due to bending is

1.  L3/48 EI

2.  L3/192 EI

3.  L3/96 EI

4.  L3/16 EI

4

L3/96 EI

Explanation :
No Explanation available for this question

# In a two dimensional stress system, it is assumed that the principal stresses σ1 and σ2 are such that σ1 >σ2; then according to the maximum shear stress theory, the failure occurs when (Where σy is yield stress, υ is Poisson’s ratio and E modulus of elasticity)

1.  1/E [σ1-υσ2] ≥ σy/E

2.  [σ12+σ22+ 2υ σ1σ2] ≥ σ2y

3.  [σ1-σ2] ≥ σy

4.  [σ12+σ22-σ1σ2] ≥ σy

4

12] ≥ σy

Explanation :
No Explanation available for this question

# The total strain energy per unit volume may be written as

1.  1/E[σ12+σ22+σ32 -2υ(σ1σ2+ σ2σ3+ σ3σ1)]

2.  1/2E[σ12+σ22+σ32 -υ(σ1σ2+ σ2σ3+ σ3σ1)]

3.  2/E[σ12+σ22+σ32 -υ(σ1σ2+ σ2σ3+ σ3σ1)]

4.  1/2E[σ12+σ22+σ32 -2υ(σ1σ2+ σ2σ3+ σ3σ1)]

4

1/2E[σ122232 -2υ(σ1σ2+ σ2σ3+ σ3σ1)]

Explanation :
No Explanation available for this question

# In strained body, three principal stresses at appoint are denoted by σ1, σ2 and σ3 such that σ1>σ2 >σ3. If σ0 denoted yield stress, then according to the maximum sheer stress theory

1.  σ1 -σ2 =σ0

2.  σ1 -σ3 =σ0

3.  σ2 -σ3 =σ0

4.  (σ1+σ3)/2 =σ0

4

σ130

Explanation :
No Explanation available for this question

# If the strain energy absorbed in a cantilever beam in bending under its own weight is K times greater than the strain energy absorbed in an identical simply supported beam in bending under its own weight, them the magnitude of K is

1.  2

2.  4

3.  6

4.  8

4

6

Explanation :
No Explanation available for this question

# The rectangular column shown in the above figure carries a load ‘P’ having eccentricities ex and ey along the x-axis and y-axis respectively. The stress at any point (x, y) is given by

1.  p/bd [1+(12ey.y)/d2 + (12ex.x)/b2]

2.  p/bd [1+(12ey.y)/b2 + (12ex.x)/d2]

3.  p/bd [1+(6ey.y)/d2 + (6ex.x)/b2]

4.  p/bd [1+6ey.y)/b2 + (6ex.x)/d2]

4

p/bd [1+(12ey.y)/d2 + (12ex.x)/b2]

Explanation :
No Explanation available for this question

# In the case of an axially loaded column machined for full bearing, the fastenings connecting the column to the base plates in gusseted base are designed for

1.  100% of the column load

2.  50% of the column load

3.  25% of the column load

4.  Erection conditions only

4

Explanation :
No Explanation available for this question

# Given that PE = crippling load given Euler Pc = load at failure due to direct compression PR = load in accordance with the Rankine’s criterion of failure Then PR is given by

1.  (PE +PC)/2

2.  √( PE ×PC)

3.  (PE .PC)/ PE +PC

4.  None of these

4

(PE .PC)/ PE +PC

Explanation :
No Explanation available for this question

# A hollow circular section of a column has external and internal diameters D and d respectively. It is subjected to a compressive load having an eccentricity e. For no tension condition at the base, which one of the following conditions should be satisfied

1.  e < ( (D2+d2)/4√D.d)

2.  e < ((D2+d2)/4√D.d)

3.  e < ((D/3+d/4)/2)

4.  e < ((D2+d2)/8D)

4

e < ((D2+d2)/4√D.d)

Explanation :
No Explanation available for this question

1.  70 N/mm2

2.  60 N/mm2

3.  50 N/mm2

4.  140 N/mm2

4