# Simple method of solving linear programming problems uses

1.  all the points in the feasible region

2.  only the corner points of the feasible region

3.  intermediate points within the infeasible region

4.  only the interior points in the feasible region

4

only the corner points of the feasible region

Explanation :
No Explanation available for this question

# The unit worth of resources R2. i.e. dual price of resources R2 in RS per kg is

1.  0

2.  1350

3.  1500

4.  2000

4

0

Explanation :
No Explanation available for this question

# The manufacture can make a maximum profit of Rs

1.   60000

2.  135000

3.   150000

4.  200000

4

135000

Explanation :
No Explanation available for this question

# On an element shown in the given figure, the stresses are σx = 110, σy = 30, πxy = 30 = πxy The radius of Mohr’s circle and the principle stresses σ1, σ2, are (in MPa)

1.  50 - 20, 120

2.  55 - 110, 30

3.  60 - 20, 140

4.  70 - 0, 140

4

50 - 20, 120

Explanation :
No Explanation available for this question

# For the state of stress shown in the above figure, normal stress acting on the plane of maximum shear stress is

1.  25 MPa compression

2.  75 MPa compression

3.  25 MPa tension

4.   75 MPa tension

4

25 MPa tension

Explanation :
No Explanation available for this question

# At a point in a member, the major principal stress is 200 MPa and the minor principal stress is compressive. If the uniaxial tensile yield stress is 250 MPa, then according to the maximum shear stress theory, the magnitude of the minor principal stress at which yielding will commence is

1.  200MPa

2.  100MPa

3.  50MPa

4.  25MPa

4

50MPa

Explanation :
No Explanation available for this question

# The plane of maximum shear has normal stress that is

1.  Maximum

2.  Minimum

3.  Zero

4.  None of these

4

Minimum

Explanation :
No Explanation available for this question

# Sets of principal stresses acting at any point in a stressed body are given below: I. {σ, 0} II. {σ, σ} III. {σ, -σ} IV. {σ, σ/2} The correct sequence of the ascending order of intensity of the maximum shear stress induced by the above sets will be

1.  I, IV, III, II

2.  II, I, IV, III

3.  I, III, IV, II

4.  II, IV, I, III

4

II, IV, I, III

Explanation :
No Explanation available for this question

# The state of stress at a point in a stressed element is shown in the given figure. The maximum tensile stress in the element will be

1.  20 N/mm2

2.  10√2 N/mm2

3.  10 N/mm2

4.  zero

4

10 N/mm2

Explanation :
No Explanation available for this question

# When σ and Young’s Modulus of Elasticity E remains constant, the energy- absorbing capacity of part subject dynamic forces, is a function of its

1.  Length

2.  Cross-section

3.  Volume

4.  None of these

4