# For a vibrating body under steady state forced vibrations, if ratio ω/ωn is very high, then phase angle would tend to approach

1.  00

2.  900

3.  1800

4.  2700

4

00

Explanation :
No Explanation available for this question

# The equation of motion for a damped viscous vibration is, 3x + 9x + 27x = 0. The damping factor will be

1.  0.25

2.  0.50

3.  0.75

4.  1.00

4

0.50

Explanation :
No Explanation available for this question

# A mass of 1 kg is attached to the end of a spring with stiffness 0.7 N/mm. The critical damping coefficient of this system will be

1.  1.40 Ns/m

2.  18.522 Ns/m

3.  52.92 Ns/m

4.  529.2 Ns/m

4

52.92 Ns/m

Explanation :
No Explanation available for this question

# A shaft has an attached disc at the centre of its length. The disc has its centre of gravity located at a distance of 2 mm from the axis of the shaft. When the shaft is allowed to vibrate in its natural bow-shaped node, it has a frequency of vibration of 10 radian/sec. When the shaft is rotated at 300 revolutions, its c.g will locate at a distance of

1.  2 mm

2.  2.25 mm

3.  2.5 mm

4.  3.00 mm

4

2.25 mm

Explanation :
No Explanation available for this question

# The equation of free vibrations of a system is x + 36 π2x = 0. Its natural frequency will be

1.  6 Hz

2.  3π Hz

3.  3 Hz

4.  6π Hz

4

6π Hz

Explanation :
No Explanation available for this question

# A slender shaft supported in two bearing at the ends carries a disc with an eccentricity e from the axis of rotation. The critical speed of shaft is N. If the disc is replaced by a second, one of the same weight but mounted with an eccentricity 2e, critical speed of the shaft in the second case will be

1.  1/2N

2.  1/√2N

3.  N

4.  2N

4

N

Explanation :
No Explanation available for this question

# For the spring mass system shown in the figure-I, the frequency of vibration is N. What will be the frequency when one more similar spring is added in series as shown in figure-II.

1.  N/2

2.  N/√2

3.  √2/N

4.  2N

4

N/√2

Explanation :
No Explanation available for this question

# The equivalent spring stiffness given in the figure will be

1.  k1k2/k1 + k2

2.  k1 + k2

3.  1/ k1 + k2

4.  k1 + k2/ k1 + k2

4

k1 + k2

Explanation :
No Explanation available for this question

# The natural frequency of the spring shown in the figure will be

1.

2.

3.

4.  None of these

4

Explanation :
No Explanation available for this question

1.  2.5 Hz

2.  3.0 Hz

3.  3.5 Hz

4.  4.5 Hz

4