Let e(k) be eccentricity of conic xy=k then value of e(1)-e(4)=

1.  √2

2.  0

3.  2

4.  -1

View Answer  
4
Correct Answer :

0


Explanation :
No Explanation available for this question

Equation of the normal to 9x2-16y2=144 at θ=π/6 is

1.  5x√3+2y√3=8

2.  2x√3+5y√3=8

3.  2x√3+5y√3=8

4.  2x√3+3y√3=8

View Answer  
4
Correct Answer :

2x√3+3y√3=8


Explanation :
No Explanation available for this question

If the line touches the hyperbola [(x2/a2)-(y2/b2)]=1at the point θ

1.  bm/a

2.  am/b

3.  a/bm

4.  b/am

View Answer  
4
Correct Answer :

b/am


Explanation :
No Explanation available for this question

The polar coordinates of the point (-1,-1) are

1.  (√2,7π/4)

2.  (√2,5π/4)

3.  (√2,3π/4)

4.  (√2,π/4)

View Answer  
4
Correct Answer :

(√2,5π/4)


Explanation :
No Explanation available for this question

The distance between the points (3,π/2)(5,π/3) is

1.  

2.  

3.  

4.  

View Answer  
4
Correct Answer :


Explanation :
No Explanation available for this question

The area of the triangle formed by the points(0,0)(3,π/2)(5,π/2) in sq.units

1.  15/8

2.  15/4

3.  15/2

4.  15

View Answer  
4
Correct Answer :

15/4


Explanation :
No Explanation available for this question

The area (in square units) of the triangle formed by the points with polar coordinates (1,0),(2,π/3) and (3,2π/3) is

1.  11/4

2.  5/4

3.  5√3/4

4.  11√3/4

View Answer  
4
Correct Answer :

5√3/4


Explanation :
No Explanation available for this question

The area of the triangle whose vertices are (a,θ),(2a,θ+π/3) and (3a,θ+2π/3) is (in sq.unit)

1.  7√3a2/4

2.  5√3a2/4

3.  3√3a2/4

4.  √3a2/4

View Answer  
4
Correct Answer :

5√3a2/4


Explanation :
No Explanation available for this question

Equation of the hyperbola with e=√2 and having the distance between the foci 1 is

1.  x2-y2=1/8

2.  x2-y2=1/6

3.  x2-y2=5

4.  x2-y2=1/4

View Answer  
4
Correct Answer :

x2-y2=1/8


Explanation :
No Explanation available for this question

The foci of the hyperbola coincides with the foci of the ellipse [(x2/25)+(y2/9)]=1.Then the equation of the hyperbola if its e=2

1.  [(x2/8)-(y2/16)]=1 y

2.  [(x2/16)-(y2/8)]=1

3.  [(x2/4)-(y2/12)]=1

4.  [(x2/12)-(y2/4)]=1

View Answer  
4
Correct Answer :

[(x2/4)-(y2/12)]=1


Explanation :
No Explanation available for this question
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