# If a random variable X take values 0 and 1 with respective probabilities 2/3 and 1/3 then the expected value of X is:

1.  2/3

2.  1/3

3.  0

4.  1

4

1/3

Explanation :
No Explanation available for this question

# The probability distribution of a random variable is given below. Its mean is (X=x)

1.  19/8

2.  5/18

3.  1

4.  4/5

4

19/8

Explanation :
No Explanation available for this question

# A random variable X has the following probability distribution, then C= (X=x)

1.  0.1

2.  0.2

3.  10

4.  20

4

0.1

Explanation :
No Explanation available for this question

# If X is a random variable with the following probability distribution given below X=x

1.  1/8,22/27

2.  1/8,23/27

3.  1/8,24/27

4.  1/8,27/36

4

1/8,27/36

Explanation :
No Explanation available for this question

# If X is a random variable with the following probability distribution X=x

1.  4

2.  3

3.  2

4.  1

4

2

Explanation :
No Explanation available for this question

# A random variable X takes values 0,1,2 its mean is 1.3 if P(X=0)=0.2, then P(X=2)=

1.  0.3

2.  0.4

3.  0.5

4.  0.2

4

0.5

Explanation :
No Explanation available for this question

# In a business venture a man can make a profit of Rs.2000/- with probability of 0.4 or have a loss of Rs.1000/- with probability 0.6his expected profit is

1.  Rs. 800/-

2.  Rs.600/-

3.  Rs.200/-

4.  Rs.400/-

4

Rs.200/-

Explanation :
No Explanation available for this question

# If it rains, a dealer in rain coats can earn Rs.500/- a day, If it is fair, he can lose Rs.40/- per day. If the probability of affair day is 0.6, his mean profit is

1.  Rs. 170/-

2.  Rs. 172/-

3.  Rs.274/-

4.  Rs.176/-

4

Rs.176/-

Explanation :
No Explanation available for this question

# If the variance of the random variable X is 4, Then the variance of the random variable 5X+10 is

1.  100

2.  10

3.  50

4.  25

4

100

Explanation :
No Explanation available for this question

1.  0

2.  1

3.  0.5

4.  3

4