Let x + y =k be a normal to the parabola y2=12x. If p is length of the perpendicular from the focus of the parabola onto this normal, then 4k - 2p2 =0

1.  1

2.  0

3.  -1

4.  2

View Answer  
4
Correct Answer :

0


Explanation :
No Explanation available for this question

If the line 2x+5y =12 intersects the ellipse 4x2+5y2 = 20 in two distinct point A and B, then Midpoint of AB is

1.  (0,1)

2.  (1,2)

3.  (1,0)

4.  (2,1)

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4
Correct Answer :

(1,2)


Explanation :
No Explanation available for this question

Equation of one of the tangents passing through (2,8) to the hyperbola 5x2- y2 = 5 is

1.  3x+y-14=0

2.  3x-y+2 =0

3.  x+y+3 =0

4.  x-y+6 =0

View Answer  
4
Correct Answer :

3x-y+2 =0


Explanation :
No Explanation available for this question

The area (in square units) of the equilateral triangle formed by the tangent at (3,0) to the hyperbola x2-3y2=3 with t

1.  √2

2.  √3

3.  1/√3

4.  2√3

View Answer  
4
Correct Answer :

√3


Explanation :
No Explanation available for this question

The radius of the circle r =12cosθ+5sinθ is

1.  5/12

2.  17/2

3.  15/2

4.  13/2

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4
Correct Answer :

13/2


Explanation :
No Explanation available for this question

If x-coordinate of a point P on the line joining the points Q(2,2,1) and R(5,1,-2) is 4,then the z-coordinate of P is

1.  -2

2.  -1

3.  1

4.  2

View Answer  
4
Correct Answer :

-1


Explanation :
No Explanation available for this question

A straight line is equally inclined to all the three coordinate axes. Then an angle made by the line with the y-axis is

1.  Cos-1(1/3)

2.  Cos-1(1/√3)

3.  Cos-1(2/√3)

4.  π/4

View Answer  
4
Correct Answer :

Cos-1(1/√3)


Explanation :
No Explanation available for this question

If the foot of the perpendicular from (0,0,0) to a plane is (1,2,3), then the equation of the plane is

1.  2x+y+3z =14

2.  x+2y+3z =14

3.  x+2y+3z+14=0

4.  x+2y -3z =14

View Answer  
4
Correct Answer :

x+2y+3z =14


Explanation :
No Explanation available for this question

The equation of the sphere through the points (1,0,0) (0,1,0) and (1,1,1) and having the smallest radius

1.  3(x2+y2+z2)-4x-4y-2z+1= 0

2.  2(x2+y2+z2)-3x-3y-z+1 =0

3.  x2+y2+z2-x-y+z+1= 0

4.  x2+y2+z2-2x-2y+4z+1= 0

View Answer  
4
Correct Answer :

3(x2+y2+z2)-4x-4y-2z+1= 0


Explanation :
No Explanation available for this question

1.  e4

2.  e6

3.  e5

4.  e

View Answer  
4
Correct Answer :

e5


Explanation :
No Explanation available for this question
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