The current density J is

1.  200/p sin(105t)up A/m2

2.  400/p sin(105t)up A/m2

3.  100/p sin(105t)up A/m2

4.  None of these

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4
Correct Answer :

100/p sin(105t)up A/m2


Explanation :
No Explanation available for this question

The following fields exist in charge free regions P=10/r cos(ωt+10x)uz Q=3r2cotf ur+cos f/r ur S=1/r sinqsin(ωt-6r)uq The possible electromagnetic fields are

1.  P, Q

2.  R, S

3.  P, R

4.  Q, S

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4
Correct Answer :

P, Q


Explanation :
No Explanation available for this question

The magnetic field intensity

1.  -4a sin (1.5 x 108t -ax)µz µA/m

2.  -4asin (1.5 x108t-ax) µz mA/m

3.  4a sin (1.5x108t–ax) µz µA/m

4.  4a sin (1.5x108t-ax) µz mA/m

View Answer  
4
Correct Answer :

4a sin (1.5x108t-ax) µz mA/m


Explanation :
No Explanation available for this question

The surface ρ=3 and 10 mm, and z= 0 and 25 cm are perfect conductors. The region enclosed by these surface has μ=2.5x10-6H/m μ=4x10-11 F/m and σ=0. If H=2/ρ cos8πzcoωtuφ A/m, then the value ω is

1.  2πx106 rad/s

2.  8πx106 rad/s

3.  2πx108 rad/s

4.  8πx108 rad/s

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4
Correct Answer :

8πx108 rad/s


Explanation :
No Explanation available for this question

For distilled water µ=µ0, =81?0, and σ=2x10-3S/m then ratio of conduction current density. displacement current density at 1 GHz is

1.  1.1×110-5

2.  4.4×10-4

3.  2.68×10-6

4.  1.68×10-7

View Answer  
4
Correct Answer :

4.4×10-4


Explanation :
No Explanation available for this question

a certain region J=(4yμx+2xzuy+z3uz)sin(104t) A/m. If volume charge density ρv in z =0 plane is zero, then ρv is

1.  3z2 cos (104t) mC/m3

2.  0 .2 cos (104t) mC/m3

3.  -3z2 cos (104t)mC/m3

4.  -0.3z2 cos (104t)mC/m3

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4
Correct Answer :

0 .2 cos (104t) mC/m3


Explanation :
No Explanation available for this question

The intrisic impedance of a conducting medium for which σ= 58 MS/m, µr=1 at a frequency f = 100 MHZ is

1.  2.14x105 450Ω

2.  1.84x10-3 ?-450Ω

3.  3.69 x 10-3?450Ω

4.  3.69 x 10-3 ?450Ω

View Answer  
4
Correct Answer :

3.69 x 10-3?450Ω


Explanation :
No Explanation available for this question

the amplitude Ei (incident) in free space (region 1) at the interface with region 2 is 1V/m. Ifμ0r(reflected) = -1.41x10-3A/m. μr2=18.5 and σ2 =0 then μr2 will be

1.  99.2

2.  198.4

3.  123

4.  none of these

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4
Correct Answer :

198.4


Explanation :
No Explanation available for this question

The depth of penetration of a wave in a lossy dielectric increase with increasing

1.  conductivity

2.  permeability

3.  wavelength

4.  permittivity

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4
Correct Answer :

wavelength


Explanation :
No Explanation available for this question

The polarisation of wave with electric field vector

1.  linear

2.  elliptical

3.  left head circular

4.  right head circular

View Answer  
4
Correct Answer :

linear


Explanation :
No Explanation available for this question
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