# In the circuit shown in the given figure , for R = 20Ω the current I is 2 A. when R is 10Ω, then current I would be

1.  1 A

2.  2 A

3.  2.5 A

4.  3 A

4

2 A

Explanation :
No Explanation available for this question

# The short – circuit test of a 2 – port network is shown in Fig.(a) .The voltage across the terminals AA` in the network shown in Fig.(b) will be

1.  20 V

2.  10 V

3.  5 V

4.  2 V

4

2 V

Explanation :
No Explanation available for this question

# In a passive two – port network, the open – circuit impedance matrix is. If input is interchanged with the output port, then open – circuit impedance matrix will be

1.

2.

3.

4.

4

Explanation :
No Explanation available for this question

# An ideal transformer has turns ratio of 2 : 1 .Considering high voltage side as port 1 and low voltage side as port 2 , then transmission line parameters of transformer will be

1.

2.

3.

4.

4

Explanation :
No Explanation available for this question

# A two – port network is defined by the relations I1 = 2V1 + V2 , I2 = 2V1 + 3V2 , Then z12 is

1.  -2 Ω

2.  -1 Ω

3.  -1/2 Ω

4.  1/4 Ω

4

-1 Ω

Explanation :
No Explanation available for this question

# With the usual notations , a two – port resistive network satisfies the condition A= D = (3/2)B = (4/3)C , z11 of the network is

1.  5/3

2.  4/3

3.  4/3

4.  1/3

4

4/3

Explanation :
No Explanation available for this question

# The driving point impedance of the infinite ladder network shown in the figure is (Given : R1 = 2Ω and R2 = 1.5 Ω)

1.  3 Ω

2.  3.5 Ω

3.  3/3.5 Ω

4.  In(1+3/3.5) Ω

4

3.5 Ω

Explanation :
No Explanation available for this question

# The driving point function of the circuit shown in the given figure where , s → 0 and s → ∞,(elements are normalized ) will respectively be

1.  1/s and 2/s

2.  1/s and 0.75

3.  0.75 and 2/s

4.  2/s and 0.75

4

1/s and 0.75

Explanation :
No Explanation available for this question

# For the given driving point impedance function Z(s) = (4s4 + 7 s2 + 1)/s(2s2 + 3) , the circuit realization is shown in the given figure . Then the values of C and L are respectively

1.  0.5 and 3

2.  2 and 1

3.  4 and 1

4.  4 and 3

4

2 and 1

Explanation :
No Explanation available for this question

# The driving point impedance Z(s) = s+2/s+2.The system is initially at rest . For a voltage signal of unit step , the current i(t) through the impedance Z is given by

1.  2 - e-t

2.  3/2 - e-3t /2

3.  3/2 - e-2t /2

4.  3 - 2 e-2t

4