For the circuit shown below, assume current gain of the transistor is 100 and VBE = 0.7V calculate the current flowing through 5 KΩ load

1.  0.782 mA

2.   7.84 mA

3.  0.078 mA

4.   0.078 A

View Answer  
4
Correct Answer :

0.782 mA


Explanation :
No Explanation available for this question

The percentage regulation of the circuit is

1.  3.5%

2.  35%

3.  4.5%

4.  None

View Answer  
4
Correct Answer :

3.5\%


Explanation :
No Explanation available for this question

For the transistor circuit shown below, the common base current gain is α = 0.9920. Determine RE & VEC such that it’s emitter current is limited to 1 mA

1.  4.01 KΩ, 3.3 V

2.  3.3 KΩ, 4.01 V

3.  4.01 KΩ, 4.01 V

4.  3.3 KΩ, 3.3 V

View Answer  
4
Correct Answer :

3.3 KΩ, 4.01 V


Explanation :
No Explanation available for this question

Consider the Op-Amp circuit shown below

1.  1+ R2/R1

2.  1+ 2 R2/R1

3.  R2/R1

View Answer  
3
Correct Answer :

1+ 2 R2/R1


Explanation :
No Explanation available for this question

For the circuit shown below, let Vr =0, the secondary voltage given by vs = Vs sinωt, where Vs = 24V. The Zener diode has parameters Vz = 16V at Iz = 40 mA and rz = 2Ω. The value of Ri such that, the load current can vary over the range 40≤IL≤400 mA

1.  100Ω

2.   36Ω

3.   10Ω

4.  18.2Ω

View Answer  
4
Correct Answer :

18.2Ω


Explanation :
No Explanation available for this question

For the circuit shown below, the voltage gain of the amplifier when current gain β=100 at T=30 K

1.  -2.0 V/V

2.   3 V/V

3.   -3 V/V

4.  It is not possible to find voltage gain as h-parameters are not given

View Answer  
4
Correct Answer :

-3 V/V


Explanation :
No Explanation available for this question

For the circuit shown below assume β = 50. What is the value of VBB & VEC such that it’s emitter current is 2.2 mA

1.   5.05V, 2.8V

2.  5.05V, 2.2V

3.  2.8V, 5.05V

4.   2.2V, 5.05V

View Answer  
4
Correct Answer :

5.05V, 2.8V


Explanation :
No Explanation available for this question

The secondary voltage in the circuit shown below is Vs = 12 sinωt the Zener diode has parameter Vz =9 V at Iz =100 mA and rz = 0.5Ω. Let Vϒ =0 and Ri = 3 Ω. Determine the percent regulation in load currents between IL = 0.2 and 1A

1.  10%

2.  0.1%

3.   0.5%

4.   5%

View Answer  
4
Correct Answer :

5\%


Explanation :
No Explanation available for this question

The 3 – dB cut off frequency of the amplifier is

1.  f3db = 1.9kHz

2.  f3db = 1.2kHz

3.  f3db = 37.2Hz

4.  f3db = 16Hz

View Answer  
4
Correct Answer :

f3db = 1.2kHz


Explanation :
No Explanation available for this question

In the non inverting amplifier shown in figure, if R1=100 kΩ, R2 = 200 kΩ and unloaded gain is infinity then what is its closed loop gain

1.  3

2.  4

3.  1

4.   2

View Answer  
4
Correct Answer :

3


Explanation :
No Explanation available for this question
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