# For the circuit shown below, assume current gain of the transistor is 100 and VBE = 0.7V calculate the current flowing through 5 KΩ load

1.  0.782 mA

2.   7.84 mA

3.  0.078 mA

4.   0.078 A

4

0.782 mA

Explanation :
No Explanation available for this question

# The percentage regulation of the circuit is

1.  3.5%

2.  35%

3.  4.5%

4.  None

4

3.5\%

Explanation :
No Explanation available for this question

# For the transistor circuit shown below, the common base current gain is α = 0.9920. Determine RE & VEC such that it’s emitter current is limited to 1 mA

1.  4.01 KΩ, 3.3 V

2.  3.3 KΩ, 4.01 V

3.  4.01 KΩ, 4.01 V

4.  3.3 KΩ, 3.3 V

4

3.3 KΩ, 4.01 V

Explanation :
No Explanation available for this question

# Consider the Op-Amp circuit shown below

1.  1+ R2/R1

2.  1+ 2 R2/R1

3.  R2/R1

3

1+ 2 R2/R1

Explanation :
No Explanation available for this question

# For the circuit shown below, let Vr =0, the secondary voltage given by vs = Vs sinωt, where Vs = 24V. The Zener diode has parameters Vz = 16V at Iz = 40 mA and rz = 2Ω. The value of Ri such that, the load current can vary over the range 40≤IL≤400 mA

1.  100Ω

2.   36Ω

3.   10Ω

4.  18.2Ω

4

18.2Ω

Explanation :
No Explanation available for this question

# For the circuit shown below, the voltage gain of the amplifier when current gain β=100 at T=30 K

1.  -2.0 V/V

2.   3 V/V

3.   -3 V/V

4.  It is not possible to find voltage gain as h-parameters are not given

4

-3 V/V

Explanation :
No Explanation available for this question

# For the circuit shown below assume β = 50. What is the value of VBB & VEC such that it’s emitter current is 2.2 mA

1.   5.05V, 2.8V

2.  5.05V, 2.2V

3.  2.8V, 5.05V

4.   2.2V, 5.05V

4

5.05V, 2.8V

Explanation :
No Explanation available for this question

# The secondary voltage in the circuit shown below is Vs = 12 sinωt the Zener diode has parameter Vz =9 V at Iz =100 mA and rz = 0.5Ω. Let Vϒ =0 and Ri = 3 Ω. Determine the percent regulation in load currents between IL = 0.2 and 1A

1.  10%

2.  0.1%

3.   0.5%

4.   5%

4

5\%

Explanation :
No Explanation available for this question

# The 3 – dB cut off frequency of the amplifier is

1.  f3db = 1.9kHz

2.  f3db = 1.2kHz

3.  f3db = 37.2Hz

4.  f3db = 16Hz

4

f3db = 1.2kHz

Explanation :
No Explanation available for this question

1.  3

2.  4

3.  1

4.   2

4