# A silicon abrupt junction has dopant concentration Na=2*1016 cm-3 and Nb=2*1015cm-3.The applied reverse bias is VR=10V the maximum electric field is 106V/cm Space charge width is

1.  2.18

2.  2.5

3.  25

4.  50

4

2.18

Explanation :
No Explanation available for this question

# A uniformly doped silicon p+n junction is to be designed such that at a reverse bias of VR=10V the maximum electric field is 106v/m. The maximum doping concentration in n region is

1.  6.4*1017cm-3

2.  6.4*1019cm-3

3.  3.2*1017cm-3

4.  3.2*1017cm-3

4

3.2*1017cm-3

Explanation :
No Explanation available for this question

# An ideal one sided silicon n*p junction has uniform doping on both sides of the abrupt junction .The doping relation is Nd=40Na.Vbi=0.75V.reverse bias VR=8V Space change width is

1.  1.8

2.  1.6

3.  1.4

4.  1.2

4

1.6

Explanation :
No Explanation available for this question

# An ideal one sided silicon n*p junction has uniform doping on both sides of the abrupt junction .The doping relation is Nd=40Na.Vbi=0.75V.reverse bias VR=8V Junction Capacitance is

1.  3.8nF/cm2

2.  9.8nF/cm2

3.  6.47nF/cm2

4.  5.4nF/cm2

4

6.47nF/cm2

Explanation :
No Explanation available for this question

# In a series voltage regulator circuit shown below find the output voltage V0, Given VBE = 0.7 V Vz = 9.3V Β = 50

1.   25V

2.  20V

3.   15V

4.  10V

4

15V

Explanation :
No Explanation available for this question

# Linearly of an Op-Amp is achieved by using which of the following.

1.  By using –ve feedback to force Op-Amp to the operate within it’s linear region

2.  Implementing feedback network with linear elements

3.  Both a & b some time along with +ve feedback

4.  Both option a & b are sufficient

4

Both option a & b are sufficient

Explanation :
No Explanation available for this question

# The correct location of Q – point for the circuit shown below is

1.

2.

3.

4.

4

Explanation :
No Explanation available for this question

# The UTP, LTP and Hysteresis width of inverting Schmit Trigger circuit shown below

1.  -5.77V, 5.77V & 11.54V

2.  5.77V, -5.77V & 5.77V

3.  -5.77V, -5.77V & 11.54V

4.  -5.77V, 5.77V & 5.77V

4

-5.77V, 5.77V & 11.54V

Explanation :
No Explanation available for this question

# The circuit shown below is, where Vin is input sinusoidal signal, (Assume Ideal diode)

1.  Half wave rectifier circuit

2.  Full wave rectifier circuit

3.  Peak detector

4.  None

4

Half wave rectifier circuit

Explanation :
No Explanation available for this question

1.  2 mA

2.  4 mA

3.   -4 mA

4.  0 mA

4