# Assuming  the signal  to be uniformly distributed between  its peak  to peak value,  the signal to noise ratio at the quantizer output is

1.  16 dB

2.  32 dB

3.  48 dB

4.  64 dB

4

48 dB

Explanation :
No Explanation available for this question

# The number of quantization levels required to reduce the quantization noise by a factor of 4 would be The  following  series  RLC  circuit  with  zero  initial  conditions  is  excited  by  a  unit  impulse functions δ(t)

1.  1024

2.  512

3.  256

4.  64

4

512

Explanation :
No Explanation available for this question

# The gain and phase margins of G(s) for closed loop stability are

1.  6dB and 180°

2.  3dB and 180°

3.  6dB and 90°

4.  3dB and 90°

4

6dB and 90°

Explanation :
No Explanation available for this question

# For t > 0, the output voltage Vc(t) is

1.  (2/√3)(e-(1/2)t– e(√(3)/2)t)

2.  (2/√3)te-(1/2)t

3.  (2/√3)e-(1/2)t cos((√(3)/2)t)

4.  (2/√3)e-(1/2)t sin((√(3)/2)t)

4

(2/√3)e-(1/2)t sin((√(3)/2)t)

Explanation :
No Explanation available for this question

# For t > 0, the voltage across the resistor is A  two  -port network shown below  is excited by external dc  source. The  voltages and  the currents  are measured with  voltmeters V1, V2  and  ammeters A1, A2  (all  assumed  to  be ideal), as indicated. Under following switch conditions, the readings obtained are: (i)  S1 - Open, S2 - Closed       A1 = 0 A, V1 = 4.5 V, V2 = 1.5 V, A2 = 1A (ii) S 1- Closed, S2  - Open       A1  = 4 A, V1 = 6 V, V2  = 6V, A2  = 0A

1.  (1/√3)(e-(√(3)/2) - e-(1/2)t)

2.  e-(1/2)t[cos(√(3t)/2) -(1/√3) sin(√(3t)/2)]

3.  (2/√3)e-(1/2)t sin(√(3t)/2)

4.  (2/√3)e-(1/2)t cos(√(3t)/2)

4

e-(1/2)t[cos(√(3t)/2) -(1/√3) sin(√(3t)/2)]

Explanation :
No Explanation available for this question

# The amplitude of a random signal is uniformly distributed between -5V and 5V.If the signal to quantization noise ratio required in uniformly quanting the signal is 43.5dB, the step size of the quantization is approximately

1.  0.0333V

2.  0.05V

3.  0.0667V

4.  0.10V

4

0.0667V

Explanation :
No Explanation available for this question

# If  the positive values of  the signal are uniformly quantized with a step size of 0.05V, and the negative values are uniformly quantized with a step size of 0.1V, the resulting signal to quantization noise ratio is approximately

1.  46dB

2.  43.8dB

3.  42dB

4.  40dB

4

40dB

Explanation :
No Explanation available for this question

# The samples x(n) n = (0, 1, 2,.....) are given by

1.  5(1 - e-0.05n)

2.  5e-0.05n

3.  5(1 - e-5n)

4.  5e-5n

4

5e-0.05n

Explanation :
No Explanation available for this question

# The expression and the region of convergence of the z-transform of the sampled signal are  n the following transistor circuit, VBE ≈ 0.7V, re = 25 mV/IE, and β all the capacitances are very large.

1.  5z/(z - e5), | z | < e-5

2.  5z/(z - e-005), | z | < e-0.05

3.  5z/(z - e-005), | z | > e-0.05

4.  5z/(z - e-5), | z | > e-5

4

5z/(z - e-005), | z | > e-0.05

Explanation :
No Explanation available for this question

1.  1 mA

2.  2 mA

3.  5 mA

4.  10 mA

4