# In the circuit shown below, the current flowing through a resistor of resistance of 100Ω would be

1.  8 mA

2.  10 mA

3.  20 mA

4.  100 mA

4

8 mA

Explanation :
No Explanation available for this question

# For the fixed bias circuit shown in below let RB = 800 KΩ. If the range of β is between 75 and 150. The change in value of RC such that Q – point will remains 2.5 V. ( i.e. VCEQ = 2.5 V)

1.  3.15 to be increased

2.  Q – point is independent of RC

3.  3.15 KΩ to be decreased

4.  None of these

4

3.15 KΩ to be decreased

Explanation :
No Explanation available for this question

# In the CASCODE amplifier shown below, if the common emitter stage (Q1) has a trans conductance gm1 ,common base stage (Q2) has a trans conductance gm2 , then the overall trans conductance is

1.  gm1

2.  gm2

3.  gm1/2

4.  gm2/2

4

gm1

Explanation :
No Explanation available for this question

# One of the applications of current mirror is

1.  output current limiting

2.  obtaining a very high current gain

3.  current feedback

4.  temperature stabilized biasing

4

temperature stabilized biasing

Explanation :
No Explanation available for this question

# For a fixed bias circuit RB = 344 KΩ, RC KΩ then the range of base current when β varies in the range 75 to 150 for the quiescent collector current of 0.5 mA. Assume base emitter voltage is constant

1.  3.3 Micro A to 6.66 Micro A

2.   6.66 Micro A to 3.3 Micro A

3.  Remain same

4.   None of these

4

Remain same

Explanation :
No Explanation available for this question

# In a 741 Op-Amp there is 20 dB/decade fall-off starting at a relatively low frequency. This is due to the

2.  Internal compensation

3.  Impedance of the source

4.  Power dissipation in the chip

4

Internal compensation

Explanation :
No Explanation available for this question

# The Darlington stage is shown if the trans conductance of Q1 is gm1 and Q2 is gm2 , then the overall trans conductance gm = ΔIC/ΔVbe is given by

1.  gm1

2.  0.5 gm

3.  gm2

4.  0.5 gm2

4

0.5 gm2

Explanation :
No Explanation available for this question

# An amplifier without feedback has a voltage gain of 50, input resistance of 1KΩ and output resistance of 2.5kΩ. The input resistance of the current –shunt negative feedback amplifier using the above amplifier with feedback of 0.2 is

1.  (1/11) KΩ

2.  (1/5) KΩ

3.  5 KΩ

4.   11 KΩ

4

(1/11) KΩ

Explanation :
No Explanation available for this question

# Which of the following represents the transfer function of given Circuit for input shown below

1.

2.

3.

4.

4 Explanation :
No Explanation available for this question

# In the circuit shown below, the transistor is biased with constant current of 0.5 mA. If β = 50 then power dissipated in the transistor and power supplied by the constant current source is

1.  3.80 m W, 3.91 Mw

2.  3.91 m W, 3.80 m W

3.  3.91 m W, 3.82 m W

4.   3.823 m W, 3.91 m W

4