# The number of roots of  s3 + 5s2+ 7s + 3=0 in the left half of the s-plane is

1.  Zero

2.  One

3.   Two

4.  Three

4

Zero

Explanation :
No Explanation available for this question

# The transfer function of a tachometer is of the form

1.   Ks

2.   K/s

3.  K(s+1)

4.  (d) K/s(s+1)

4

Ks

Explanation :
No Explanation available for this question

# Consider a unity feedback control system with open-loop transfer function G(s) = K/[s(s+1)]. The steady state error of the system due to a unit step input is

1.   Zero

2.  K

3.  1/k

4.  ∞

4

Zero

Explanation :
No Explanation available for this question

# The transfer function of a zero-order-hold system is

1.   (1/s) (1+e-st)

2.   (1/s) (1-e-st)

3.  1-(1/s)e-st)

4.  1-(1/s)e-st)

4

(1/s) (1-e-st)

Explanation :
No Explanation available for this question

# In the Bode-plot of a unity feedback control system, the value of phase of G(jω) at the gain cross over frequency is -125°. The phase margin of the system is

1.   -125°

2.  -55°

3.  55°

4.   125°

4

55°

Explanation :
No Explanation available for this question

# Consider a feedback control system with loop transfer function

1.   Zero

2.   One

3.  Two

4.  Three

4

One

Explanation :
No Explanation available for this question

# The transfer function of a phase lead controller is (1+3Ts)/(1+Ts). The maximum value of phase provided by this controlled is

1.  90

2.   60°

3.  45°

4.  30°

5.  Of

6.  With

7.  In

8.    No correction is needed

9.  154 cm2

10.  168 cm2

11.  308 cm2

13.  None of these

13

None of these

Explanation :
No Explanation available for this question

# The Nyquist plot of a loop transfer function g(jω) H(jω) of a system encloses the (-1, jo) point. The giant margin of the system is

1.  Less than zero

2.  Zero

3.  Greater than zero

4.   Infinity

5.  Rotating

6.  Encircling

7.  Dodging

8.  Spinning

9.  22 cm2

10.  44 cm2

11.  77 cm2

12.  154 cm2

12

77 cm2

Explanation :
No Explanation available for this question

# The transfer function of a system is

1.  2s2+6s+5=0

2.   (s+1)2(s+2)= 0

3.   2s2+6s+5+9(s+1)2 (s+2) = 0

4.  2s2+6s+5-(s+1)2 (s+2) = 0

4

(s+1)2(s+2)= 0

Explanation :
No Explanation available for this question

1.   -2

2.  -1

3.  1

4.  2

4