The excitation voltage (E) and load angle (δ) will respectively be

1.  0.8 pu and 36.860 lag

2.   0.8 Pu and 36.860 lead

3.  1.17 pu and 30.960 lead

4.  1.17 pu and 30.960 lag

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Explanation :
No Explanation available for this question

Keeping the excitation voltage same, the load on the motor is increased such that the motor current increases by 20%. The operating power factor will become

1.  0.995 lagging

3.  0.791 lagging

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Explanation :
No Explanation available for this question

A function y(t) satisfies the following differential equation.Where δ(t) is the delta function. Assuming zero initial condition,and denoting the unit step function by  u(t),y(t) can be of the form

1.  et

2.  e-t

3.  et u(t)

4.  e-t u(t)

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e-t u(t)

Explanation :
No Explanation available for this question

Two point Charges Q = 10 µC and Q1 = 20 µC are placed at coordinates (1, 1, 0) and (-1 - 1 0) respectively. The total electric flux passing through a plane z = 20 will be

1.  7.5 µC

2.  13.5 µC

3.  15.0 µC

4.  22.5 µC

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15.0 µC

Explanation :
No Explanation available for this question

The speed of rotation of stator magnetic field with respect to rotor structure will be

1.  90 rpm in the direction of rotation

2.  90 rpm in the opposite direction of rotation

3.  1500 rpm in the direction of rotation

4.  1500 rpm in the opposite direction of rotation

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90 rpm in the direction of rotation

Explanation :
No Explanation available for this question

Neglecting all losses of both the machines, the dc generator power output and the current through resistance (Rex) will respectively be

1.  96 W, 3.10 A

2.  120 W, 3.46 A

3.  1504 W, 12.26 A

4.  1880 W, 13.71 A

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1504 W, 12.26 A

Explanation :
No Explanation available for this question

In the figure Ra,Rb and Rc are 20Ω,10Ω and 10Ω respectively.The resistance R1,R2 and R3 in Ω of an equivalent star-connection are

1.  2.5,5,5

2.  5,2.5,5

3.  5,5,2.5

4.  2.5,5.2.5

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2.5,5,5

Explanation :
No Explanation available for this question

.In the figure the admittance values of the elements in Siemens are YR=0.5+j0.Y1=0-J1.5.YC=0+J0.3 respectively.the value of I as a phasor when the voltage E across the elements is 10 is

1.  1.5+j0.5

2.  5-j18

3.  0.5+j1.8

4.  5-j12

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5-j12

Explanation :
No Explanation available for this question

In figure,the value of resistance R in Ω is

1.  10

2.  20

3.  30

4.  40

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40

Explanation :
No Explanation available for this question

1.  14.7 A

2.  18.5 A

3.  40.0 A

4.  50.0 A

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