# The population for the year 1895 will be

1.  46,000

2.  54,850

3.  82,000

4.  none of these

4
Correct Answer :

54,850

Explanation :
No Explanation available for this question

# The population for the year 1925 will be

1.  54,850

2.  46000

3.  96840

4.  none of these

4
Correct Answer :

96840

Explanation :
No Explanation available for this question

# Tenth term of the series will be

1.  1

2.  10

3.  100

4.  none of these

4
Correct Answer :

100

Explanation :
No Explanation available for this question

# First terms of the series respectively will be

1.  100, 1

2.  10, 1

3.  100, 0.1

4.  100,10

4
Correct Answer :

100, 0.1

Explanation :
No Explanation available for this question

# tan (0.12) will be

1.  0.0205

2.  0.1205

3.  0.2662

4.  0.1205

4
Correct Answer :

0.1205

Explanation :
No Explanation available for this question

# tan (0.26) will be

1.  0.0205

2.  0.1205

3.  0.2662

4.  0.3662

4
Correct Answer :

0.2662

Explanation :
No Explanation available for this question

# The Newton-Raphson iteration xn+1=xn/2 +3/2xn can be used to solve the equation

1.  x2 = 3

2.  x3 = 3

3.  x2 = 2

4.  x3 = 2

4
Correct Answer :

x2 = 3

Explanation :
No Explanation available for this question

# Which of the following statements applies to the bisection method used for finding roots of functions

1.  Converges within a few iterations

2.  Guaranteed to work for all continuous functions

3.  It is faster than the Newton-Raphson method

4.  Requires that there be no error in determining the sign of the function

4
Correct Answer :

Guaranteed to work for all continuous functions

Explanation :
No Explanation available for this question

# The Newton-Raphson method is used to find the root of the equation x2-2 = 0. If iterations are started from -1, the iterations will be

1.  converge to -1

2.  converge to √2

3.  converge to -√2

4.  not converge

4
Correct Answer :

converge to -√2

Explanation :
No Explanation available for this question

# Newton-Raphson iteration formula for finding, where c > 0, is

1.  Xn+1= (2x3n +)/3x2n

2.  Xn+1= (2x2n -)/3x2n

3.  Xn+1= (2x3n +c)/3x2n

4.  Xn+1= (2x2n -c)/3x2n

4
Correct Answer :

Xn+1= (2x3n +c)/3x2n

Explanation :
No Explanation available for this question

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