The circuit of given figure is used for generating sinusoidal oscillations. What is the frequency of oscillations

1.  CR

2.  

3.  

4.  

View Answer  
4
Correct Answer :


Explanation :
No Explanation available for this question

The circuit of given figure is used for generating sinusoidal oscillations. What is the value of R’

1.  R’= R

2.  R’=2R

3.  R’=R/2

4.  R’=R/4.

View Answer  
4
Correct Answer :

R’=2R


Explanation :
No Explanation available for this question

A JFET having µ=50 and rd=10k is used in a common source configuration as shown in the figure below, the JFET capacitances are: Cgs=5pF, Cgd=2pF, and Cds=2pF ac small-signal mid band voltage gain (V0 /VS) will be

1.  -15

2.  -20

3.  -25

4.  -30.

View Answer  
4
Correct Answer :

-25


Explanation :
No Explanation available for this question

A JFET having μ=50 and rd=10kΩ is used in a common source configuration as shown in the figure below, the JFET capacitances are: Cgs=5pF,Cgd=2pF,andCds=2p Upper 3Db frequency of the circuit will be

1.  12.9MHz

2.  13.9MHz

3.  14.9MHz

4.  15.9MHz.

View Answer  
4
Correct Answer :

15.9MHz.


Explanation :
No Explanation available for this question

Consider the above circuit, for Vi =Vm  sin t, the output voltage V0 for RLà will be

1.  Zero

2.  Vm

3.  2Vm

4.  –Vm

View Answer  
4
Correct Answer :

2Vm


Explanation :
No Explanation available for this question

The correct waveform for output (V0) for the above network is

1.  

2.  

3.  

4.  

View Answer  
4
Correct Answer :


Explanation :
No Explanation available for this question

The output Vdc from the above circuit is

1.  12√2

2.  12/π

3.  24/π

4.  12/√2.

View Answer  
4
Correct Answer :

12/π


Explanation :
No Explanation available for this question

The figure given below shows the transfer characteristics of

1.  Peak clipper

2.  Bottom clipper

3.  Clamper

4.  Two level clipper.

View Answer  
4
Correct Answer :

Peak clipper


Explanation :
No Explanation available for this question

The figure shown below is a circuit of

1.  Bridge rectifier

2.  Voltage doubler

3.  Rectifier with filter

4.  Comparator.

View Answer  
4
Correct Answer :

Voltage doubler


Explanation :
No Explanation available for this question

An amplifier has gain A=100 1800, upper cut-off frequency of 100kHz and lower cut-off frequency of 1KHz. A negative feedback of β=0.1 is added. Which one of the following is not correct

1.  Gain becomes 100/11

2.  Lower cut-off frequency becomes (1000/11) Hz

3.  Upper cut-off frequency becomes 1.1 MHz

4.  dB of feedback is 20 log10 11.

View Answer  
4
Correct Answer :

dB of feedback is 20 log10 11.


Explanation :
No Explanation available for this question
Previous Next

Interview Questions

MongoDB
Java Script
Node JS
PHP
JQuery
Python