1.  

2.  

3.  

4.  

4
Correct Answer :


Explanation :
No Explanation available for this question

1.  h[n] = 0; n < 0, n > 2, h[0] = 1, h[1] = h[2] = - 1

2.  h[n] = 0; n < -1, n > 1, h[-1] = 1, h[0] = h[1] = 2

3.  h[n] = 0; n < 0, n > 3, h[0] = -1, h[1] = 2, h[2] = 1

4.  h[n] = 0; n < - 2, n > 1, h[- 2] = h[1] = h[-1] = - h[0] = 3

4
Correct Answer :

h[n] = 0; n < 0, n > 2, h[0] = 1, h[1] = h[2] = - 1


Explanation :
No Explanation available for this question

1.  (1 - h/H)2 dr

2.  (1 - h/H)2 dh

3.  H(1 - r/R) dh

4.  H (1 - (r/R))2 dr

4
Correct Answer :

H (1 - (r/R))2 dr


Explanation :
No Explanation available for this question

1.  y1[n] ↔ Y1(z) =

2.  y2[n] ↔ Y2(z) =

3.  y3[n] ↔ Y3(z) =

4.  y4[n] ↔ Y4(z) = 2z-4 + 3z-2 + 1

4
Correct Answer :

y1[n] ↔ Y1(z) =


Explanation :
No Explanation available for this question

1.  17√2

2.  17/√2

3.  √(2)/17

4.  0

4
Correct Answer :

0


Explanation :
No Explanation available for this question

1.  only when x (t) is bounded

2.  only when x (t) is non-negative

3.  only for t ≥ 0 if x (t) is bounded for t ≥ 0

4.  even when x (t) is not bounded

4
Correct Answer :

even when x (t) is not bounded


Explanation :
No Explanation available for this question

1.  has no finite singularities in its double sided Laplace Transform Y (s)

2.  produces a bounded output for every causal bounded input

3.  produces a bounded output for every anticausal bounded input

4.  has no finite zeroes in its double sided Laplace Transform Y (s)

4
Correct Answer :

produces a bounded output for every causal bounded input


Explanation :
No Explanation available for this question

1.  Pr (r > 6) = 1/6

2.  Pr (r/3 is an integer) = 5/6

3.  Pr (r = 8 | r/4 is an integer) = 5/9

4.  Pr (r = 6 | r/5 is an integer) = 1/18

4
Correct Answer :

Pr (r = 8 | r/4 is an integer) = 5/9


Explanation :
No Explanation available for this question

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