1.  Increasing temperature

2.  Lowering temperature

3.  Adding a catalyst

4.  Removing the products

4
Correct Answer :

Adding a catalyst


Explanation :
No Explanation available for this question

1.  100

2.  49.95

3.  10

4.  1000

4
Correct Answer :

10


Explanation :
No Explanation available for this question

1.  0.213sec-1

2.  2.31sec-1

3.  0.0231sec-1

4.  2.31x10-3sec-1

4
Correct Answer :

0.0231sec-1


Explanation :
No Explanation available for this question

1.  Rate =k[O3]2

2.  Rate =k[O3]2[O2]-1

3.  Rate =k[O3][O2]

4.  Rate =k[O3][O2]-1

4
Correct Answer :

Rate =k[O3]2[O2]-1


Explanation :
No Explanation available for this question

1.  0.1mol L-1min-1

2.  0.3mol L-1min-1

3.  1mol L-1min-1

4.  0.4 mol L-1min-1

4
Correct Answer :

0.1mol L-1min-1


Explanation :
No Explanation available for this question

1.  Whose rate is not affected by concentration

2.  In which the reactants do not react

3.  In which one of the reactants is in large excess

4.  In which concentration of reactants changed with time

4
Correct Answer :

Whose rate is not affected by concentration


Explanation :
No Explanation available for this question

1.  It is independent of initial concentration

2.  It decreases with the introduction of a catalyst

3.  It increases with increase of temperature

4.  It is inversely proportioanl to rate constant

4
Correct Answer :

It increases with increase of temperature


Explanation :
No Explanation available for this question

1.  molliter-1sec-1

2.  mol-1 litre sec-1

3.  sec-1

4.  mol2 litre-2 sec-1

4
Correct Answer :

sec-1


Explanation :
No Explanation available for this question

1.  Rate =-d[N2]/dt=-1/3d[H2]/dt=12d[NH3]/dt

2.  Rate =-d[N2]/dt=-3d[H2]/dt=2d[NH3]/dt

3.  Rate =d[N2]/dt=-1/3d[H2]/dt=1/2d[NH3]/dt

4.  Rate =-d[N2]/dt=-d[H2]/dt=d[NH3]/dt

4
Correct Answer :

Rate =-d[N2]/dt=-1/3d[H2]/dt=12d[NH3]/dt


Explanation :
No Explanation available for this question

1.  By increasing temperature

2.  By using a suitable catalyst

3.  By increasing activation energy

4.  By increasing the concentration of reactant

4
Correct Answer :

By increasing activation energy


Explanation :
No Explanation available for this question

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