# What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years

1.  1 : 3

2.  1 : 4

3.  2 : 3

5.   None of these

5

2 : 3

Explanation :
No Explanation available for this question

# 8, 7, 11, 12, 14, 17, 17, 22, (__)

1.  27

2.   20

3.  22

4.  24

4

20

Explanation :
No Explanation available for this question

# A sum fetched total simple interest of 4016.25 at the rate of 9 p.c.p.a. in 5 years.What is the sum?

1.  8925

2.  ?8032.50

3.  ?4462.50

4.  ?8900

5.  None of these

5

8925

Explanation :
No Explanation available for this question

# The remainder, when (1523 + 2323) is divided by 19, is

1.  4

2.  15

3.  0

4.  18

4

0

Explanation :
No Explanation available for this question

# What is the number of digits in 484 × 512

1.  13

2.  12

3.  14

4.  16

4

16

Explanation :
No Explanation available for this question

# M, N, O and P divided `44352 among themselves. M took 3/8 th of the money, N took 1/6 of the remaining amount and rest was divided among O and P is the ratio of 3 : 4 respectively. How much did O get as his share

1.  `9600

2.  `10600

3.  `10300

4.   `8700

5.  `9900

5

`9900

Explanation :
No Explanation available for this question

# 52.416÷18.72+6.28 =

1.  2.09664

2.  8.36

3.  9.08

4.  9.80

4

9.08

Explanation :
No Explanation available for this question

# The probability that a student is not a swimmer is 1/5. Then the probability that one of the five students, four are swimmers is:

1.  5C4 (4/5)2 (1/5)

2.  (4/5)4 (1/5)

3.  5C4 (1/5) (4/5)4

4.  None of these

4

5C4 (1/5) (4/5)4

Explanation :
No Explanation available for this question

# What is the probability of getting a sum 9 from two throws of a dice

1.  1/6

2.  1/8

3.  1/9

4.  1/12

4

1/9

Explanation :
No Explanation available for this question

# Sum of digits of a 5 digit number is 41. Find the probability that such a number is divisible by 11

1.  2/15

2.  11/36

3.  3/35

4.  6/35

4

6/35

Explanation :
No Explanation available for this question

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