A. (100)²
B. √10
C. 100
D. 10
E. 10√10
If a + b + c = 13, a2 + b2 + c2 = 69, then find ab + bc + ca.
If in a code, 52 – 36 = 97 and 46 – 78 = 1510, then how 53 – 62 can be encoded?
The value of 1001 + 11 of 13 is:
415% of 620 =?
(2√27-√75+√12) is equal to:
76% of (?) – (11)² = 525
9050 ÷ 40=?
7080÷925 X 741 - 172 =?
39815 + 42305 = 122678-?
24*22=? ÷8