In a parallel plate air capacitor of capacitance 4 farad, if the lower half of air space is filled with a material of dielectric constant 3 its capacitance changes to

Two charges of +200μC and -200μC are placed at the corners B and C of an equilateral triangle ABC of side 0.1m.The force on a charge of 5μC placed at A is

A rod with linear charge density λ is bent in the shape of circular ring.The electric potential at the centre of the circular ring is

A proton of mass m charge e is released from rest in a uniform electric field of strength E.The time taken by it to travel a distance d in the field is

The energy stored in a sphere of 10cm radius when the sphere is charged to a potential of 300 volt is

The potential energy of a proton is 3.2x10^-18J at a particular point. The electric potential at this point is

Capacitance of a capacitor becomes 7/6 times its original value if a dielectric slab of thickness,t=2/3d is introduced in between the plates.d is the separation between the plates.The dielectric constant of the di-electric slab is

Two wires A and B,made of same material and having their lengths in the ratio 6:1 are connected in series.The potential differences across the wires are 3V and 2V respectively.If r_A and r_B the radii of A and B respectively,then r_A/r_B is

When a dielectric slab of the same area of cross-section and thickness equal to 2/3 of the separation is introduced between the plates of a parallel plate capacitor, its capacitance becomes 2.25 times the original value. The dielectric constant of the material of the slab is

A charge of 10 units is divided so that force between the two charges is maximum when placed 2cm apart. The two charges are