A. cos 8θ+8cos 6θ+28cos 4θ+56cos 2θ+35
B. cos 8θ+8cos 6θ-28cos 4θ+56cos 2θ+35
C. cos 8θ-8cos 6θ+28cos 4θ-56cos 2θ+35
D. cos 8θ+8cos 6θ-28cos 4θ-56cos 2θ+35
128 sin8 θ=
27 cos5 θsin3 θ=
The last terms in the expantions of sin 8θ, sin 9θ respectively are
If cos α+ cos β=0= sin α + sin β then cos(α - β)=
If 16 sin5 θ=asin 5 θ+b sin 3θ+c sin θ then
64cos3 θsin4 θ=