A. nπ or (3n±1)π/9: n ε Z
B. nπ/3 + (-1)n π/6: n ε Z
C. 2nπ/3 ± π/9: n ε Z
D. nπ/3 + π/18: n ε Z
If tan (πcos x) = cot (π sinx) then cos(x-π/4) =
If 6 Sec2 θ-5 Sec θ+1=0 then θ=
If cot θ - tan θ= sec θ, then θ =
If sin x-3 sin 2x+sin 3x=cos x-3cos 2x+cos 3x then x=
If cos θ+cos 2θ+ cos 3θ=0 then θ=
If tan (π/2 sin θ) = cot (π/2 cos θ) then sin (θ+ π/4) =
If tan x+ tan 4x+tan 7x=tan x tan 4x tan 7x, then x=
If cos 2θ+cos 8θ= cos 5θ then θ=
If 2-cos3 θ=3 sin θ cos θ then θ=
The solution of sin 2θ+cos 2θ+sin θ+ cos θ+1=0 in the first quadrant is