If tan A,tan B are the roots of x²-px+q=0,the value of sin²(A+B) is

The equation cos⁴x-(a+2)cos²x-(a+3) =0 possesses a solution if

If 4 sin x.sin 2x.sin 4x=sin 3x then x=

If tan (πcos x) = cot (π sinx) then cos(x-π/4) =

If 6 Sec² θ-5 Sec θ+1=0 then θ=

If cot θ - tan θ= sec θ, then θ =

If sin x-3 sin 2x+sin 3x=cos x-3cos 2x+cos 3x then x=

If cos θ+cos 2θ+ cos 3θ=0 then θ=

If tan (π/2 sin θ) = cot (π/2 cos θ) then sin (θ+ π/4) =

If tan x+ tan 4x+tan 7x=tan x tan 4x tan 7x, then x=