If a= sin(Cot^-1 x)and b= cot(Sin^-1 x) where x>0, then 1/x² – x²=

tan (1/2 cos^-1(0)) =

If θ= Sin^-1 x+ Cos^-1 x+ Tan^-1 x, 0≤x≤1, then the smallest interval in which θ lies is given by

If cos^-1 x= cot^-1(4/3)+Tan^-1(1/7), then x=

If sin^-1 (3/5)+sin^-1(5/13)= sin^-1 x, then x=

Tan^-1 5/6+ 1/2 Tan^-1 11/60 =

The range of Sin^-1 5x is

Sin (4 arc Tan^-11/3) =