A. 29/27
B. -29/27
C. 27/11
D. -27/29
2 Tan-1 1/3+Tan-1 1/7=
Sin (2Tan-13/4) =
Tan-1 3/2-Tan-11/5 =
If tan-1 2, tan-13 are two angles of a triangle, then the third angle is
Two angles ofa triangle are Cot-1 2 and Cot-1 3.Then the third angle is
The domain of Sinh-1 2x is
If a= sin(Cot-1 x)and b= cot(Sin-1 x) where x>0, then 1/x2 – x2=
tan (1/2 cos-1(0)) =
If θ= Sin-1 x+ Cos-1 x+ Tan-1 x, 0≤x≤1, then the smallest interval in which θ lies is given by
If cos-1 x= cot-1(4/3)+Tan-1(1/7), then x=