A. 0
B. 1
C. xyz
D. 2xyz
Sin-1 (16/65) +2 Tan-1 (1/5) =
If Cot-1 4/3+Cot-1 5/3= Tan-1 k, then k=
2 Tan-1 1/3+Tan-1 1/7=
Sin (2Tan-13/4) =
Tan-1 3/2-Tan-11/5 =
If tan-1 2, tan-13 are two angles of a triangle, then the third angle is
Two angles ofa triangle are Cot-1 2 and Cot-1 3.Then the third angle is
The domain of Sinh-1 2x is
If a= sin(Cot-1 x)and b= cot(Sin-1 x) where x>0, then 1/x2 – x2=
tan (1/2 cos-1(0)) =