The locus of the midpoint its of chords of x2/a2-y2/b2=1 which pass through the focus (ae, 0) is

A. x2/a2-y2/b2 +xe/a=0

B. x2/a2+y2/b2 +xe/a=0

C. x2/a2-y2/b2 -xe/a=0

D. x2/a2+y2/b2 -xe/a=0

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1

Correct Answer :
x2/a2-y2/b2 -xe/a=0

Explanation :
No Explanation available for this question

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