A. 1/(1+x)2
B. 2/(1+x)3
C. -2/(1+x)3
D. none
d/dx{(√(a2+x2)+ √(a2-x2))/ (√(a2+x2)- √(a2-x2))}
d/dx{Tan-1√(1-x/1+x)}=
If x2-xy+y2=1 and y’’(1)=
d/dx{Tan-1(x-√x/1+x3/2}=
If 3x2+4xy+2y2+x-8=0 and dy/dx at (1,1),(1,2),(2,-1),(-1,3) are respectively A,B,C,D then the descending order of A,B,C,D is
d/dx { log√(cosec x+1)-√(cosec x-1)}=
The derivative of (sin x)x w.r.to x is
If |x|<1 then d/dx[1+px/q+p(p+q)/2!(x/q)2+p(p+q)(p+2q)/3! (x/q)3+...]
Let f(x)=1/|x| for |x| ≤1, f(x)=ax2+b for |x|>1. If f is differentiable at any point, then
The derivative of Tan-1√(1+x2)-1/x w.r.to Tan-12x√(1-x2)/(1-2x2) at x=0 is