A. y[2/3x-5+3x/x2+1-5/2x+3-2x/3x2-1]
B. y[2/3x-5+3x/x2+1-5/2x+3+2x/3x2-1]
C. y[2/3x-5-3x/x2+1-5/2x+3+2x/3x2-1]
D. y[2/3x-5+3x/x2+1+5/2x+3-2x/3x2-1]
d/dx{Tan-1(3a2x-x3/a3-3ax2)}=
d/dx{Tan-1√(1+x2)+√(1-x2)/(√(1+x2)-√(1-x2))}=
Ify=ae-bx cos(cx+d) then y2+2by1+(b2+c2)y=
d/dx{Tan-13x-x3/1-3x2}=
If f(x)=√(1-√(1-x2)), then
If x2+y2=a2 then (1+y12)3/2/|y2|=
The derivative of (x2+1)5(2x+3)3 w.r.t is
If x= a(2 cos θ+cos 2θ), y= a(2 sin θ+sin 2θ)then dy/dx=
If y= x log|x+√(1+x2)|-√(1+x2) then dy/dx=
d/dx{√(1+cos x)/sin x}=