If y= {(3x-5)^2/3(x²+1)^3/2/(2x+3)^5/2(3x²-1)^1/3}then dy/dx=

d/dx{Tan^-1(3a²x-x³/a³-3ax²)}=

d/dx{Tan^-1√(1+x²)+√(1-x²)/(√(1+x²)-√(1-x²))}=

Ify=ae^-bx cos(cx+d) then y₂+2by₁+(b²+c²)y=

d/dx{Tan^-13x-x³/1-3x²}=

If f(x)=√(1-√(1-x²)), then

If x²+y²=a² then (1+y₁²)^3/2/|y₂|=

The derivative of (x²+1)⁵(2x+3)³ w.r.t is

If x= a(2 cos θ+cos 2θ), y= a(2 sin θ+sin 2θ)then dy/dx=

If y= x log|x+√(1+x²)|-√(1+x²) then dy/dx=