A. -1/2√(1-x2)
B. 1/1+x2
C. 2/1+x2
D. 2/√(1-x2)
If a,b,c are the fifth terms of loge(3/2), loge(4/3), loge(6/5) then the ascending order of a,b,c is
If y= {(3x-5)2/3(x2+1)3/2/(2x+3)5/2(3x2-1)1/3}then dy/dx=
d/dx{Tan-1(3a2x-x3/a3-3ax2)}=
d/dx{Tan-1√(1+x2)+√(1-x2)/(√(1+x2)-√(1-x2))}=
Ify=ae-bx cos(cx+d) then y2+2by1+(b2+c2)y=
d/dx{Tan-13x-x3/1-3x2}=
If f(x)=√(1-√(1-x2)), then
If x2+y2=a2 then (1+y12)3/2/|y2|=
The derivative of (x2+1)5(2x+3)3 w.r.t is
If x= a(2 cos θ+cos 2θ), y= a(2 sin θ+sin 2θ)then dy/dx=