A. (y/x)1/3
B. - (y/x)1/3
C. x2-ay/ax-y2
D. –y(2x+y)/x(x+2y)
d/dx{cos-1√(1+x)/2}=
If a,b,c are the fifth terms of loge(3/2), loge(4/3), loge(6/5) then the ascending order of a,b,c is
If y= {(3x-5)2/3(x2+1)3/2/(2x+3)5/2(3x2-1)1/3}then dy/dx=
d/dx{Tan-1(3a2x-x3/a3-3ax2)}=
d/dx{Tan-1√(1+x2)+√(1-x2)/(√(1+x2)-√(1-x2))}=