A. C,A,B
B. B,A,C
C. A,C,B
D. A,B,C
The solution of extan y dx+(1-ex)sec2ydy=0 is
If the equation λx2 – 5xy + 6y2 + x -3y=0, represents a pair of straight lines, then their point of intersection is
If A and B are two square matrices such that B=A-1 BA, then (A+B)2 is equal to
The solution of y dx-x dy+log x dx=0 is
The solution of (12x+5y-9)dx+(5x+2y-4)dy=0 is
The solution of (x+y+1)dx+(3x+4y+4)dy=0 is
Solution of differential equation dy/dx = (1+y2) (1+x2)-1is
The line 4x + 6y + 9=0, touches the parabola y2=4x at the point
The solution of 3excos2ydx+(1-ex)cot y dy=0 is
x2+y2=t+(1/t),x4+y4=t2+(1/t2)⇒x3y(dy/dx)=