A. (14/41)+i.0
B. 15+i.0
C. 14-i.0
D. 15-i.0
(1-i)(1+2i)(1-3i)=
(3+5ω+3ω2)6=
The modulus of (3-4i)(4+5i) is
The conjugate of (1+2i) (2-3i) is
If x=-5+4i then x4+9x3+35x2-x+4=
The modules of √3+i/(1+i)(1+√3i) is
(1+ω-ω2) (1-ω+ω2)=