If a and b are numbers between 0 and 1 such that the points z₁= a+i, z₂= 1+bi and z₃= 0 from an equilateral triangle then a,b are

i²+i^-4+i^-6+…(2n+1) terms

(1-ω+ω²)(1-ω²+ω⁴) (1-ω⁴+ω⁸) (1-ω⁸+ω¹⁶)=

If z= (λ+3)+i√(5-λ²), then the locus of z is a circle with centre at

If x= -5+4i then x⁴+9x³+35x²-x+4=

The modulus of (3-4i)(4+5i) is

Express (3-2i/ 5+4i)+ (3+2i/ 5-4i) in the form of a+ib

(1-i)(1+2i)(1-3i)=

(3+5ω+3ω²)⁶=

The modulus of (3-4i)(4+5i) is