If a circle passes through the point (a, b) and cuts the circle x2+y2=k2 orthogonally, the equation of the locus of its centre is

A. 2ax+2by=a2+b2+k2

B. ax+by=a2+b2+k2

C. x2+y2+2ax+2byk2=0

D. x2+y2-2ax+2byk2=0

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1

Correct Answer :
2ax+2by=a2+b2+k2

Explanation :
No Explanation available for this question

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