A. x2+y2+2x-2y-62=0

B. x2+y2+2x+2y-47=0

C. x2+y2-12x-2y-7=0

D. x2+y2-2x+2y-62=0

The circle x^{2}+y^{2}-4x+4y-1=0 cuts the positive coordinate axes in A and B respectively. The equation to the diameter of the circle perpendicular to the chord AB is

If the equation of the circle cutting orthogonally the circles x^{2}+y^{2}-6x=0, x^{2}+y^{2}+4x+3y+1=0 and which has its centre on the line x+2y=5 is x^{2}+y^{2}-2ax-2by+c=0 then the descending order of a, b, c is

The radius of the circle passing through the point (6, 2) and two of whose diameters are x+y=6 and x+2y=4 is

The locus of the midpoints of the chords of the circle 4x^{2}+4y^{2}-12x+4y+1=0 which subtend an angle of π/3 at its centre is a circle of radius

Let P be a point on the circle x^{2}+y^{2}=9, Q a point on the line 7x+y+3=0, and the perpendicular bisector of PQ be the line x-y+1=0. Then the coordinates of P are